我有两个 2D python 字典,我想获得一个 2D 字典,其中键是前两个字典键的并集,值是 1d 字典的串联。如果一维字典中存在重复键,我希望获得它们值的总和。
所以,假设我:
dict1 = { 1: {2: 0.1, 3: 0.3, 4: 0.4} ,
2 :{1: 0.2, 3: 0.3, 4: 0.5} }
dict2 = { 2: {1: 0.1, 3: 0.8, 5: 0.4} ,
3 :{1: 0.2, 2: 0.8, 4: 0.5} }
我期望的是:
merged_dict = { 1: {2: 0.1, 3: 0.3, 4: 0.4} ,
2 :{1: 0.3, 3: 1.1, 4: 0.5 , 5: 0.4} ,
3: {1: 0.2, 2: 0.8, 4: 0.5} }
我目前使用的是 python 3.2.3
最佳答案
这里没什么特别的,但你总是可以做类似的事情:
merged_dict = dict1.copy()
for key, val in dict2.iteritems():
if key not in dict1:
merged_dict[key] = val
else:
for key2, val2 in val.iteritems():
if key2 not in dict1[key]:
merged_dict[key][key2] = val2
else:
merged_dict[key][key2] += val2
(抱歉,这是 python 2.7)
此外,如果您想使用defaultdict
:
from collections import defaultdict
merged_dict = defaultdict(dict)
for key, val in dict1.iteritems():
merged_dict[key] = defaultdict(int, val)
for key, val in dict2.iteritems():
if key not in merged_dict:
merged_dict[key] = defaultdict(int, val)
else:
for key2, val2 in val.iteritems():
merged_dict[key][key2] += val2
关于python - 合并两个2D字典python,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33731985/