python - 无法使用python在selenium中截取警告框的屏幕截图

Question

我是 selenium 的新手，我想在弹出警报时截取警报框的屏幕截图。 我写的代码如下:

import unittest
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.common.exceptions import NoAlertPresentException
import time


class SearchXSS(unittest.TestCase):

def setUp(self):
    self.driver = webdriver.Firefox()

def test_search_in_python_org(self):
    driver = self.driver
    driver.get("http://testfire.net/")
    ele = driver.find_element_by_name("txtSearch")
    ele.send_keys("<script>alert(document.cookie)</script>")
    ele.send_keys(Keys.RETURN)
    try:
        time.sleep(1)
        alert = driver.switch_to_alert()
        driver.get_screenshot_as_file('screenshot.png')
        alert.accept()
    except NoAlertPresentException as e:
        print "no alert to accept "
    fo.close()


def tearDown(self):
    self.driver.quit()

if __name__=="__main__":
    unittest.main()

我在截屏的时候遇到了这个问题，报错信息如下

====================================================================== ERROR: test_search_in_python_org (main.SearchXSS) ---------------------------------------------------------------------- Traceback (most recent call last): File "/home/user/programs/sele/testx.py", line 22, in test_search_in_python_org driver.get_screenshot_as_file('screenshot.png') File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py", line 798, in get_screenshot_as_file png = self.get_screenshot_as_png() File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py", line 817, in get_screenshot_as_png return base64.b64decode(self.get_screenshot_as_base64().encode('ascii'))
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py", line 827, in get_screenshot_as_base64 return self.execute(Command.SCREENSHOT)['value'] File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py", line 236, in execute self.error_handler.check_response(response) File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/errorhandler.py", line 191, in check_response raise exception_class(message, screen, stacktrace, value['alert'].get('text')) UnexpectedAlertPresentException: Alert Text: amSessionId=92632533494 Message: Unexpected modal dialog (text: amSessionId=92632533494) Stacktrace: at fxdriver.modals.closeUnhandledAlert/< (file:///tmp/tmpdnEJbt/extensions/fxdriver@googlecode.com/components/prompt-service.js:4745) at (http://testfire.net/search.aspx?txtSearch=%3Cscript%3Ealert%28document.cookie%29%3C%2Fscript%3E:80)

---------------------------------------------------------------------- Ran 1 test in 10.346s

FAILED (errors=1) [Finished in 10.4s with exit code 1]

帮我解决这个问题。

Answer 1

你不能用alert框截取screenshot，你需要先处理alert意味着accept或者dismiss 然后去截屏，因为当 selenium 去截取带有警报的屏幕截图时，它总是会抛出 UnexpectedAlertPresentException，无法截取使用 selenium 的 alert 框截图。所以你需要做如下:-

alert = driver.switch_to_alert()
alert.accept()
driver.get_screenshot_as_file('screenshot.png')

如果你想使用 alert 截屏，你应该尝试使用其他库的一些不同方法，在 java 中有 Robot 类可以截取 screenshot 在这种情况下，但我不确定 python 中的等效项是什么。