Python - 如何提取包含引用标记的句子？

Question

text = "Trondheim is a small city with a university and 140000 inhabitants. Its central bus systems has 42 bus lines, serving 590 stations, with 1900 (departures per) day in average. T h a t gives approximately 60000 scheduled bus station passings per day, which is somehow represented in the route data base. The starting point is to automate the function (Garry Weber, 2005) of a route information agent."
print re.findall(r"([^.]*?\(.+ [0-9]+\)[^.]*\.)",text)

我正在使用上面的代码来提取其中包含引用的句子。正如您所看到的，最后一句包含引文(Garry Weber，2005)。

但是我得到了这个结果:

[' Its central bus systems has 42 bus lines, serving 590 stations, with 1900 (departures per) day in average. T h a t gives approximately 60000 scheduled bus station passings per day, which is somehow represented in the route data base. The starting point is to automate the function (Garry Weber, 2005) of a route information agent.']

结果应该是仅包含引用的句子，如下所示:
出发点是实现路线信息代理功能的自动化(Garry Weber，2005)。

我猜问题是由括号内的文本引起的，正如您在它包含的第二行中看到的那样(出发次数)，我的代码有什么解决方案吗？

Answer 1

我的尝试。 Live demo .

\b[^.]+\([^()]+\b(\d{2}|\d{4})\s*\)[^.]*\.

它准确地捕捉了句子，并且比您的年份更具体。