在 panel.py
中,引用类中 buttonA
的类无法发出信号。
但是在panel2.py
中引用buttonA
类就可以实现
如果想在panel.py
类中重复使用buttonA
类,如何处理这样的问题。尝试继承buttonA
类只能发生一次btnA1
buttonA.py
#!/usr/bin/env python
from PyQt5.QtWidgets import QWidget, QPushButton, QVBoxLayout, QApplication
class ButtonA(QWidget):
def __init__(self):
super().__init__()
def createButton(self):
self.btnA1 = QPushButton("btnA1", self)
self.btnA1.pressed.connect(self.onbtnA1Pressed)
self.btnA1.released.connect(self.onbtnA1Released)
vbox = QVBoxLayout()
vbox.addWidget(self.btnA1)
return vbox
def onbtnA1Pressed(self):
self.btnA1.setText("btnA1 clicked")
def onbtnA1Released(self):
self.btnA1.setText("btnA1")
panel.py
#!/usr/bin/env python
from PyQt5.QtWidgets import QWidget, QVBoxLayout, QApplication
import sys, buttonA
class Panel(QWidget):
def __init__(self):
super().__init__()
def createPanel(self):
a1 = buttonA.ButtonA()
a2 = buttonA.ButtonA()
v1 = a1.createButton()
v2 = a2.createButton()
vbox = QVBoxLayout()
vbox.addLayout(v1)
vbox.addLayout(v2)
self.setLayout(vbox)
if __name__ == "__main__":
app = QApplication(sys.argv)
p = Panel()
p.createPanel()
p.show()
sys.exit(app.exec_())
panel2.py
#!/usr/bin/env python
from PyQt5.QtWidgets import QApplication, QWidget, QVBoxLayout
import buttonA, sys
app = QApplication(sys.argv)
w = QWidget()
a1 = buttonA.ButtonA()
a2 = buttonA.ButtonA()
v1 = a1.createButton()
v2 = a2.createButton()
vbox = QVBoxLayout()
vbox.addLayout(v1)
vbox.addLayout(v2)
w.setLayout(vbox)
w.show()
sys.exit(app.exec_())
最佳答案
在 panel.py
中,在 createPanel
函数中,声明实例变量时必须使用实例,在本例中为 self
。
这应该有效:
面板.py
#!/usr/bin/env python
from PyQt5.QtWidgets import QWidget, QVBoxLayout, QApplication
import sys, buttonA
class Panel(QWidget):
def __init__(self):
super().__init__()
def createPanel(self):
self.a1 = buttonA.ButtonA()
self.a2 = buttonA.ButtonA()
self.v1 = self.a1.createButton()
self.v2 = self.a2.createButton()
vbox = QVBoxLayout()
vbox.addLayout(self.v1)
vbox.addLayout(self.v2)
self.setLayout(vbox)
if __name__ == "__main__":
app = QApplication(sys.argv)
p = Panel()
p.createPanel()
p.show()
sys.exit(app.exec_())
关于python - python pyqt5 类引用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46889571/