python - 根据正则表达式结果创建具有 0 和 1 值的新列

Question

我的数据框有值:

data_df

0         student
1         sample text
2         student
3         no students
4         sample texting
5         random sample

我使用正则表达式提取包含单词“student”的行，结果如下:

regexdf
0         student
2         student

我的目标是在主数据框中创建一个包含 0 和 1 值的新列。即第 0 行应该是 1，第 5 行应该是 0。(因为“regexdf”在第 0 行和第 2 行中有“student”)如何匹配两者中的索引并创建列？

Answer 1

使用正则表达式:

data_df = data_df.assign(regexdf = data_df[1].str.extract(r'(student)\b', expand=False))
data_df['student'] = data_df['regexdf'].notnull().mul(1)
print(data_df)

输出:

                 1  regexdf  student
0         student  student        1
1     sample text      NaN        0
2         student  student        1
3     no students      NaN        0
4  sample texting      NaN        0
5   random sample      NaN        0

编辑

df_out = data_df.join(regexdf, rsuffix='regex')

df_out['pattern'] = df_out['1regex'].notnull().mul(1)

df_out['Count_Pattern'] = df_out['pattern'].cumsum()

print(df_out)

输出:

                1   1regex  pattern  Count_Pattern
0         student  student        1              1
1     sample text      NaN        0              1
2         student  student        1              2
3     no students      NaN        0              2
4  sample texting      NaN        0              2
5   random sample      NaN        0              2