我正在一家模型工厂工作,我正在尝试填写一个有选择列表的字段。当我尝试使用工厂创建一个对象并尝试从选择列表中填充随机选择时,会引发异常:
TypeError: 'choice' is an invalid keyword argument for this function
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "/usr/local/lib/python2.7/dist-packages/factory/base.py", line 551, in build
return cls._generate(enums.BUILD_STRATEGY, kwargs)
File "/usr/local/lib/python2.7/dist-packages/factory/base.py", line 505, in _generate
return step.build()
File "/usr/local/lib/python2.7/dist-packages/factory/builder.py", line 279, in build
kwargs=kwargs,
File "/usr/local/lib/python2.7/dist-packages/factory/base.py", line 312, in instantiate
return self.factory._build(model, *args, **kwargs)
File "/usr/local/lib/python2.7/dist-packages/factory/base.py", line 531, in _build
return model_class(*args, **kwargs)
File "/usr/local/lib/python2.7/dist-packages/django/db/models/base.py", line 571, in __init__
raise TypeError("'%s' is an invalid keyword argument for this function" % list(kwargs)[0])
TypeError: 'choice' is an invalid keyword argument for this function
使用的版本:
django==1.11
factory-boy==2.9.2
python==2.7.12
(裁剪后的)模型:
class Server(models.Model):
TEST = 'test'
ACCEPT = 'accept'
SERVER_TYPES = (
(TEST, _("Testing Server")),
(ACCEPT, _("Acceptation Server"))
)
type = models.CharField(_("Server type"), max_length=50, choices=SERVER_TYPES)
(裁剪后的)工厂:
class ServerFactory(factory.DjangoModelFactory):
type = factory.Faker('random_element', elements=[choice[0] for choice in Server.SERVER_TYPES)
class Meta:
model = Server
我没有使用 Faker('random_element, elements=[..])
,而是尝试使用 LazyFunction
:
def get_server_type():
choices = [choice[0] for choice in Server.SERVER_TYPES]
return random.choice(choices)
class ServerFactory(factory.DjangoModelFactory):
organization = factory.SubFactory(OrganizationFactory)
type = factory.LazyFunction(get_server_type)
.. Meta ..
这也会引发相同的错误。我也找不到任何真正的其他替代方案来解决这个问题。对于如何在使用 factory
包时使用 SERVER_TYPES
选项之一填充 type
字段,有什么建议吗?
最佳答案
你能试试这个吗?
from random import choice
type = factory.LazyAttribute(lambda x: choice(Server.SERVER_TYPES)[0])
基于问题最初描述的旧评论:
应该是type =factory.Faker('random_element', elements=[choice[0] for choice in Server.SERVER_TYPES])
关于python - Django 工厂男孩 : fill modelfield with choices throws error,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49371682/