我想从以下 xml 格式中提取问题 (type='q') 和答案 (type='a') 对作为单个数据点:
<?xml version="1.0" encoding="us-ascii"?>
<transcript id="001" >
<body>
<section name="Q&A">
<speaker id="0">
<plist>
<p>Thank you. We'll now be conducting the question-and-answer session. <mark type="Operator Instructions" /> Thank you. Please go ahead with your question.</p>
</plist>
</speaker>
<speaker id="3" type="q">
<plist>
<p>Good morning. First of all, Happy New Year.</p>
</plist>
</speaker>
<speaker id="2" type="a">
<plist>
<p>Happy New Year, sir.</p>
</plist>
</speaker>
<speaker id="3" type="q">
<plist>
<p>Thank you. How is your pain now?.</p>
</plist>
</speaker>
<speaker id="2" type="a">
<plist>
<p>Oh, it's better now. I think i am healing.</p>
</plist>
</speaker>
</section>
</body>
</transcript>
即输出应该是这样的:['早上好。首先祝大家新年快乐。新年快乐，先生。”，“谢谢。”你现在疼痛怎么样？哦，现在好多了。我想我正在康复。']
有人可以帮我用 BeautifulSoup 来做这个吗？我当前的代码提取所有 <p>文档中的标签，但问题是还有其他部分(“Q&A”除外)，其 <p>标签被提取。
soup = BeautifulSoup(handler, "html.parser")
texts = []
for node in soup.findAll('p'):
text = " ".join(node.findAll(text=True))
#text = clean_text(text)
texts.append(text)
最佳答案
您可以使用 find_all('speaker', type='q') 和 find_all('speaker', type='a')< 查找所有问题和所有答案 分别。然后使用zip将相应的问题及其答案连接起来。
代码:
questions = soup.find_all('speaker', type='q')
answers = soup.find_all('speaker', type='a')
for q, a in zip(questions, answers):
print(' '.join((q.p.text, a.p.text)))
输出:
Good morning. First of all, Happy New Year. Happy New Year, sir.
Thank you. How is your pain now?. Oh, it's better now. I think i am healing.
如果您希望将其放在列表中，可以使用列表理解:
q_and_a = [' '.join((q.p.text, a.p.text)) for q, a in zip(questions, answers)]
print(q_and_a)
# ['Good morning. First of all, Happy New Year. Happy New Year, sir.',
# "Thank you. How is your pain now?. Oh, it's better now. I think i am healing."]
关于python - Beautiful Soup 根据类型提取内容，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/51147540/