javascript - 在使用 Jquery 打开弹出窗口之前检查它是否已经打开

Question

我想在打开弹出窗口之前检查弹出窗口是否已经打开。 我如何使用 Jquery 完成它？

下面是我打开一个新弹出窗口的代码:

window.open("mystopchat.php?stat=1&session="+data['myid1']['session_id'][i],"win1","width=500,height=500"); 

在我调用它之前，我想确定这个弹出窗口还没有打开。

Answer 1

这是我使用的一个小技巧，也许你可以使用它:

var winRef; //This holds the reference to your page, to see later it is open or not

function openWindow() {  
    var url = //Your URL;
    if (typeof (winRef) == 'undefined' || winRef.closed) {
        //create new, since none is open
        winRef = window.open(url, "_blank");
    }
    else {
        try {
            winRef.document; //if this throws an exception then we have no access to the child window - probably domain change so we open a new window
        }
        catch (e) {
            winRef = window.open(url, "_blank");
        }

        //IE doesn't allow focus, so I close it and open a new one
        if (navigator.appName == 'Microsoft Internet Explorer') {
            winRef.close();
            winRef = window.open(url, "_blank");
        }
        else {
            //give it focus for a better user experience
            winRef.focus();
        }
    }
}

希望对您有所帮助。