示例模型.py
模型.py
class Food(models.Model):
name = models.CharField(max_length=50, verbose_name='Food')
def __str__(self):
return self.name
假设我已经编写了单元测试:
from django.test import TestCase
from myapp.models import Food
class TestWhateverFunctions(TestCase):
"""
This class contains tests for whatever functions.
"""
def setUp(self):
"""
This method runs before the execution of each test case.
"""
Food.objects.create(name='Pizza') # Will the created object have id of 1?
Food.objects.create(name='Pasta') # Will the created object have id of 2?
def test_if_food_is_pizza(self):
"""
Test if the given food is pizza.
"""
food = Food.objects.get(id=1)
self.assertEqual(food.name, 'Pizza')
def test_if_food_is_pasta(self):
"""
Test if the given food is pasta.
"""
food = Food.objects.get(id=2)
self.assertEqual(food.name, 'Pasta')
我想知道是否可以安全地假设在 setUp() 方法 中创建的对象的 ID 总是从 id 1
开始,依此类推?如果不是,是否有特定原因导致测试数据库在运行所有测试后总是被破坏?
最佳答案
假设 ID 总是从 1 开始并递增是不安全的。如果其他测试已预先运行并创建了 Food
行,并且单元测试未按任何保证顺序执行,则它们可能具有更高的 ID。
在测试设置中保存对模型实例的引用:
class TestWhateverFunctions(TestCase):
def setUp(self):
self.food1 = Food.objects.create(name='Pizza')
self.food2 = Food.objects.create(name='Pasta')
关于python - Django 单元测试 - 创建对象的 ID,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58242885/