我有一个嵌套字典，如何获取具有公共(public)键值(例如 37、74 等)的值:
myDict = {0: {37.0: {'C23H27O9': 'C22H23O10'}},
1: {74.0: {'C23H27O9': 'C21H19O11'}},
2: {111.0: {'C23H27O9': 'C20H15O12'}},
3: {148.0: {'C23H27O9': 'C19H11O13'}},
4: {37.0: {'C22H23O10': 'C21H19O11'}},
5: {74.0: {'C22H23O10': 'C20H15O12'}},
6: {111.0: {'C22H23O10': 'C19H11O13'}},
7: {37.0: {'C21H19O11': 'C20H15O12'}},
8: {74.0: {'C21H19O11': 'C19H11O13'}},
9: {37.0: {'C20H15O12': 'C19H11O13'}}
}
期望的输出:
37.0 --> C23H27O9: C22H23O10: C21H19O11 : C20H15O12 : C19H11O13
74.0 --> C23H27O9 : C21H19O11 : C19H11O13
...
最佳答案
您可以使用itertools.groupby:
from itertools import groupby as gb
myDict = {0: {37.0: {'C23H27O9': 'C22H23O10'}}, 1: {74.0: {'C23H27O9': 'C21H19O11'}}, 2: {111.0: {'C23H27O9': 'C20H15O12'}}, 3: {148.0: {'C23H27O9': 'C19H11O13'}}, 4: {37.0: {'C22H23O10': 'C21H19O11'}}, 5: {74.0: {'C22H23O10': 'C20H15O12'}}, 6: {111.0: {'C22H23O10': 'C19H11O13'}}, 7: {37.0: {'C21H19O11': 'C20H15O12'}}, 8: {74.0: {'C21H19O11': 'C19H11O13'}}, 9: {37.0: {'C20H15O12': 'C19H11O13'}}}
d = sorted([(a, [j for k in b.items() for j in k]) for i in myDict.values() for a, b in i.items()], key=lambda x:x[0])
r = [(a, [*{i for _, j in b for i in j}]) for a, b in gb(d, key=lambda x:x[0])]
输出:
[(37.0, ['C19H11O13', 'C20H15O12', 'C21H19O11', 'C22H23O10', 'C23H27O9']), (74.0, ['C19H11O13', 'C20H15O12', 'C21H19O11', 'C22H23O10', 'C23H27O9']), (111.0, ['C20H15O12', 'C19H11O13', 'C23H27O9', 'C22H23O10']), (148.0, ['C23H27O9', 'C19H11O13'])]
关于python - 获取嵌套字典中的公共(public)值，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/58977585/