如何根据时间字符串对这样的多维列表进行排序?子列表可以有不同的大小(即此处的 4 和 5)
我想通过比较每个子列表中的第一个时间字符串(sublist[-4])来排序
x =
(['1513', '08:19PM', '10:21PM', 1, 4],
['1290', '09:45PM', '11:43PM', 1, 4],
['0690', '07:25AM', '09:19AM', 1, 4],
['0201', '08:50AM', '10:50AM', 1, 4],
['1166', '04:35PM', '06:36PM', 1, 4],
['0845', '05:40PM', '07:44PM', 1, 4],
['1267', '07:05PM', '09:07PM', 1, 4],
['1513', '08:19PM', '10:21PM', 1, 4],
['1290', '09:45PM', '11:43PM', 1, 4],
['8772', '0159', '12:33PM', '02:43PM', 1, 5],
['0888', '0570', '09:42PM', '12:20AM', 1, 5],
['2086', '2231', '04:10PM', '06:20PM', 1, 5])
排序结果为
sortedX =
(['0690', '07:25AM', '09:19AM', 1, 4],
['0201', '08:50AM', '10:50AM', 1, 4],
['1166', '04:35PM', '06:36PM', 1, 4],
['0845', '05:40PM', '07:44PM', 1, 4],
['1267', '07:05PM', '09:07PM', 1, 4],
['1513', '08:19PM', '10:21PM', 1, 4],
['1513', '08:19PM', '10:21PM', 1, 4],
['1290', '09:45PM', '11:43PM', 1, 4],
['1290', '09:45PM', '11:43PM', 1, 4],
['8772', '0159', '12:33PM', '02:43PM', 1, 5],
['2086', '2231', '04:10PM', '06:20PM', 1, 5],
['0888', '0570', '09:42PM', '12:20AM', 1, 5])
我尝试了以下方法:
sortedX = sorted(x, key=lambda k : k[-4]) #k[-4] is the first time string
它可以工作,但它不尊重子列表大小排序
最佳答案
通过字符串比较时间可能会有错误,因为字符串是按字典顺序比较的:
>>> '02:00PM' > '12:00PM'
False
>>> '2' > '100'
True
因此,首先使用 time.strptime
将这些时间字符串转换为时间对象。
>>> import time
>>> import pprint
def func(x):
return (len(x), time.strptime(x[-4], '%I:%M%p'))
...
>>> pprint.pprint(sorted(x, key=func))
[['0690', '07:25AM', '09:19AM', 1, 4],
['0201', '08:50AM', '10:50AM', 1, 4],
['1166', '04:35PM', '06:36PM', 1, 4],
['0845', '05:40PM', '07:44PM', 1, 4],
['1267', '07:05PM', '09:07PM', 1, 4],
['1513', '08:19PM', '10:21PM', 1, 4],
['1513', '08:19PM', '10:21PM', 1, 4],
['1290', '09:45PM', '11:43PM', 1, 4],
['1290', '09:45PM', '11:43PM', 1, 4],
['8772', '0159', '12:33PM', '02:43PM', 1, 5],
['2086', '2231', '04:10PM', '06:20PM', 1, 5],
['0888', '0570', '09:42PM', '12:20AM', 1, 5]]
要按多个值排序,请使用元组,在您的情况下,第一项是长度和时间对象,第二项是长度和时间对象。
关于Python按时间字符串对二维列表进行排序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19869065/