python - 在Python中从列表构建字符串

Question

 [['Demo-Site', '10.227.209.139'], ['Demo-Site', '10.227.215.68'], 
['Demo-Site', '172.18.74.146'], ['Site', '10.152.114.65'], 
['Site', '10.227.211.244'], ['Demo-Site', '10.227.147.98'], 
 ['test', '172.18.74.146']]

如何根据第一个索引是否相同将所有 IP 连接起来形成一个大字符串？我要制作默认词典吗？

应该是:

["Site", "10.227.211.244, 10.152.114.65"]

Answer 1

这里，使用基于 defaultdict 的解决方案:

In [1]: list_of_ips = [['Demo-Site', '10.227.209.139'], ['Demo-Site', '10.227.215.68'], 
   ...: ['Demo-Site', '172.18.74.146'], ['test', '10.152.114.65'], 
   ...: ['Site', '10.227.211.244'], ['Demo-Site', '10.227.147.98'], 
   ...:  ['test', '172.18.74.146']]

In [2]: from collections import defaultdict

In [3]: resp_dict = defaultdict(list)

In [4]: for item in list_of_ips:
   ...:     resp_dict[item[0]].append(item[1])
   ...:     

In [5]: result = [[key, ", ".join(resp_dict[key])] for key in resp_dict]

In [6]: result
Out[6]: 
[['test', '10.152.114.65, 172.18.74.146'],
 ['Site', '10.227.211.244'],
 ['Demo-Site', '10.227.209.139, 10.227.215.68, 172.18.74.146, 10.227.147.98']]