python - 统计频率，如何每次取两个单词？

Question

["this","example"]:1  , ["is","silly"]:1  ....

类似的东西。 我可以处理单个单词的情况，但是如何访问两个元素并让它们成为键？

with open(sys.argv[1], 'rb') as f:
    word_list = f.read().lower()

    unwanted = ['(', ')', '\\', '"', '\'','.',';',':','!']

    for c in unwanted:
        word_list = word_list.replace(c," ")

    words = word_list.split()

    fdic = {}

    for word in words:

        # form dictionary how can you let key be pair of item?
        fdic[word] = fdic.get(word,0) + 1

Answer 1

您可以使用列表理解迭代原始单词列表来获取二元组列表:

bigrams = [word_list[i] + " " + wordlist[i+1] for i in range(len(wordlist)-1)]