我试图通过将字典键和 numpy 数组拼接在一起来创建一个新元组,并将其转换为列表。但是,我收到此错误
TypeError: list indices must be integers, not tuple
这是我的代码
import numpy
import random
print(ly)
{(1, 3): 2, (5, 2): 1, (10, 1): 0}
def myFun(layout):
possibilities = numpy.zeros(shape=(4,2))
possibilities[0] = [1, 0]
possibilities[1] = [-1, 0]
possibilities[2] = [0, 1]
possibilities[3] = [0, -1]
newLayout = tuple()
for i in layout:
randomDirection = random.choice( possibilities )
newLayout = newLayout + layout.keys()[i] + list(randomDirection)
解释器显示这一行
newLayout = newLayout + layout.keys()[i] + list(randomDirection)
有问题,但我不明白为什么
最佳答案
而不是在代码中newLayout = newLayout + layout.keys()[i] + list(randomDirection)
使用以下内容,
newLayout = newLayout + 布局[i] + list(randomDirection)
解决你的问题
关于python - 从列表和字典创建新元组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44897317/