假设我在 PyQt5 应用程序中使用文件对话框打开了一个名为 file1.mp3 的文件,并将其分配给如下变量:
song = QFileDialog.getOpenFileName(self, "Open Song", "~", "Sound Files (*.mp3 *.ogg *.wav *.m4a)")
print(song[0])
url = QUrl.fromLocalFile(song[0])
self.playlist.addMedia(QMediaContent(url))
如何获取文件名而不是文件路径,以便将其显示在状态栏中?或者更好的是,我可以使用或创建类似“正在播放”的功能吗?
最佳答案
有几种简单的方法可以获取文件名:
- 使用
QUrl
:
song, _ = QFileDialog.getOpenFileName(self, "Open Song", "~", "Sound Files (*.mp3 *.ogg *.wav *.m4a)")
print(song)
url = QUrl.fromLocalFile(song)
self.playlist.addMedia(QMediaContent(url))
your_statusbar.showMessage("now playing {}".format(url.fileName()))
- 使用
QFileInfo
:
song, _ = QFileDialog.getOpenFileName(self, "Open Song", "~", "Sound Files (*.mp3 *.ogg *.wav *.m4a)")
print(song)
url = QUrl.fromLocalFile(song)
self.playlist.addMedia(QMediaContent(url))
filename = QFileInfo(song).fileName()
your_statusbar.showMessage("now playing {}".format(filename))
- 使用
路径库
:
song, _ = QFileDialog.getOpenFileName(self, "Open Song", "~", "Sound Files (*.mp3 *.ogg *.wav *.m4a)")
print(song)
url = QUrl.fromLocalFile(song)
self.playlist.addMedia(QMediaContent(url))
from pathlib import Path
filename = Path(song).name
your_statusbar.showMessage("now playing {}".format(filename))
- 使用
操作系统
:
song, _ = QFileDialog.getOpenFileName(self, "Open Song", "~", "Sound Files (*.mp3 *.ogg *.wav *.m4a)")
print(song)
url = QUrl.fromLocalFile(song)
self.playlist.addMedia(QMediaContent(url))
import os
filename = song.rstrip(os.sep)
your_statusbar.showMessage("now playing {}".format(filename))
或:
song, _ = QFileDialog.getOpenFileName(self, "Open Song", "~", "Sound Files (*.mp3 *.ogg *.wav *.m4a)")
print(song)
url = QUrl.fromLocalFile(song)
self.playlist.addMedia(QMediaContent(url))
import os
_ , filename = os.path.split(os.sep)
your_statusbar.showMessage("now playing {}".format(filename))
关于python - 从打开的文件中获取文件名,而不是文件路径,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49217347/