python - python 将骰子的两个结果相加

Question

我是Python的绝对初学者，但我真的很想挑战自己。我想创建一个游戏，为每个玩家(目前是两个玩家)掷骰子两次。骰子的结果相加，如果是偶数则加 10 分，如果是奇数则减去 5 分。玩家最多可以玩 5 轮。到目前为止，我已将代码保留在 while 循环内，并导入 random 来“掷”骰子，但我不知道如何将随机结果添加在一起。

我的代码可能完全错误，但我希望得到一些有关如何修复它的帮助和建议(这是在 python 3 上完成的)

我的代码:

person1_name = input("What is your name: ")
person2_name = input("What is your name: ")

import random
number = random.randint(1,6)
rounds = "yes"
while rounds == "yes":
    print(person1_name, "- 1st roll = ",number, " and 2nd roll = ",number)
    total_1 = number + number
    if total_1 % 2 == 0:
        total_1 = total_1 + 10
        print(person1_name," has ",total_1, "points")
    else:
        total_1 = total_1 - 5
        print(person1_name, " has ",total_1, "points")
    print(person2_name, "- 1st roll = ",number, "and 2nd roll = ",number)
    total_2 = number + number
    if total_2 % 2 == 0:
        total_2 = total_2 + 10
        print(person2_name," has ",total_2, "points")
    else:
        total_2 = total_2 - 5
        print(person2_name," has ",total_2, "points")
    rounds = input("Do you want to play again (yes/no): ")

Answer 1

您可以使用random.choices()直接得到总和.

sum_dices = sum(random.choices(range(1,7),k=2))

或直接检查:

if sum(random.choices(range(1,7),k=2)) % 2:
     pass
else:
     pass