Python 字典列表并根据特定情况创建另一个字典

Question

我有一个字典列表。

    data = [
    {'@timestamp': '2018-10-29T05:57:12.722Z','messages': '[FANATIC] - - Session id kajdhrg7uhdfvbshfgadf '},
    {'@timestamp': '2018-10-29T06:58:12.722Z','messages': '[FANATIC] - - Exception Lorem Ipsum Rebolt '},
    {'@timestamp': '2018-10-29T06:58:12.722Z','messages': 'JHUSHDVCHBASJd'},
    {'@timestamp': '2018-10-29T06:58:12.722Z','messages': 'asdfawerg cdv '},
    {'@timestamp': '2018-10-29T06:58:12.722Z','messages': 'fya7 5 Lorem Ipsum Rebolt '},
    {'@timestamp': '2018-10-29T06:58:12.722Z','messages': 'zxcgwrt asdfg w4e6354gdf '},
    {'@timestamp': '2018-10-29T06:58:12.722Z','messages': 'zcfb26 eqrgsfdb syh2456ytdfg '},
    {'@timestamp': '2018-10-29T06:58:12.722Z','messages': 'we57hb354gf '},
    {'@timestamp': '2018-10-29T06:59:12.722Z','messages': '[FANATIC] - - sdfsum Rebolt '},
    {'@timestamp': '2018-10-29T06:59:12.722Z','messages': '[FANATIC] - - sdfsum Rebolt '}
    ]

这是一个日志模式。但错误日志新行没有 [FANATIC]，它应该在单行或单条消息中。

有没有办法将这些内容放入新字典中，并仅包含错误的共轭消息？

for i in data:
    if "[FANATIC]" in i['messages'] and "exception" in i['messages']:
        print(i)

我是否可以在新字典中捕获“行间”？

编辑:

我想要的类似于下面...:

data = [
{'@timestamp': '2018-10-29T06:58:12.722Z','messages': '[FANATIC] - - Exception Lorem Ipsum Rebolt '},
{'@timestamp': '2018-10-29T06:58:12.722Z','messages': 'JHUSHDVCHBASJd'},
{'@timestamp': '2018-10-29T06:58:12.722Z','messages': 'asdfawerg cdv '},
{'@timestamp': '2018-10-29T06:58:12.722Z','messages': 'fya7 5 Lorem Ipsum Rebolt '},
{'@timestamp': '2018-10-29T06:58:12.722Z','messages': 'zxcgwrt asdfg w4e6354gdf '},
{'@timestamp': '2018-10-29T06:58:12.722Z','messages': 'zcfb26 eqrgsfdb syh2456ytdfg '},
{'@timestamp': '2018-10-29T06:58:12.722Z','messages': 'we57hb354gf '},
{'@timestamp': '2018-10-29T06:58:12.722Z', 'messages': [
'[FANATIC] - - Exception Lorem Ipsum Rebolt', 
'JHUSHDVCHBASJd', 
'asdfawerg cdv ', 
'fya7 5 Lorem Ipsum Rebolt ',
'zxcgwrt asdfg w4e6354gdf ',
'we57hb354gf '
]
},
{'@timestamp': '2018-10-29T06:58:12.722Z','messages': '[FANATIC] - - sdfsum Rebolt '},
{'@timestamp': '2018-10-29T06:58:12.722Z','messages': '[FANATIC] - - sdfsum Rebolt '}
]

Answer 1

只需使用理解来过滤您的列表:

res = [x for x in data if x["messages"].startswith("[FANATIC]")]

或者对于这两项检查:

res2 = [x for x in data if all(s in x["messages"] for s in ("Exception", "FANATIC"))]

要获取“行间”的内容，您可以从左侧和右侧剥离:

def StriptStuff(s):
    return s.lstrip("[FANATIC] -").rstrip("- Exception Lorem Ipsum Rebolt ")

res2 = [StriptStuff(x["messages"]) for x in data if all(s in x["messages"] for s in ("Exception", "FANATIC"))]

但是对于更复杂的东西，正则表达式会更好。

这里有一个live example