python - 删除多个嵌套列表中的重复列表项

Question

我有以下列表:

values = [
    ['registrationController', 'regBean', 'firstName'],
    ['registrationController', 'regBean', 'surname'],
    ['registrationController', 'regBean', 'userName'],
    ['registrationController', 'regBean', 'password'],
    ['registrationController', 'regBean', 'confirmPassword'],
    ['registrationController', 'regBean', 'emailAddress'],
    ['registrationController', 'regBean', 'confirmEmail'],
    ['registrationController', 'regBean', 'securityQuestionAndAnswerOne', 'question'],
    ['registrationController', 'regBean', 'securityQuestionAndAnswerOne', 'answer'],
    ['registrationController', 'regBean', 'securityQuestionAndAnswerTwo', 'question'],
    ['registrationController', 'regBean', 'securityQuestionAndAnswerTwo', 'answer'],
    ['registrationController', 'regBean', 'securityQuestionAndAnswerThree', 'question'],
    ['registrationController', 'regBean', 'securityQuestionAndAnswerThree', 'answer'],
    ['registrationController', 'regBean', 'tAndCAccepted']
]

我正在尝试找出如何删除此列表中所有预设值并在 当他们变得独一无二时，他们会得到这样的东西:

unique_values = [
    ['firstName'],
    ['surname'],
    ['userName'],
    ['password'],
    ['confirmPassword'],
    ['emailAddress'],
    ['confirmEmail'],
    ['securityQuestionAndAnswerOne', 'question'],
    ['securityQuestionAndAnswerOne', 'answer'],
    ['securityQuestionAndAnswerTwo', 'question'],
    ['securityQuestionAndAnswerTwo', 'answer'],
    ['securityQuestionAndAnswerThree', 'question'],
    ['securityQuestionAndAnswerThree', 'answer'],
    ['tAndCAccepted']
]

有什么想法可以实现这个目标吗？我尝试了各种方法，但无法真正接近可行的解决方案。

Answer 1

使用集合交集来获取所有公共(public)元素和嵌套列表理解来构建清理后的列表:

common = set(values[0])
for lst in values[1:]:
    common = common.intersection(lst)

unique_values = [[v for v in lst if v not in common] for lst in values]