我有一个由两列组成的数据框:
'String' -> numpy 数组,如 [47, 0, 49, 12, 46]
“等值线”-> 1 或 0
String Is Isogram
0 [47, 0, 49, 12, 46] 1
1 [43, 50, 22, 1, 13] 1
2 [10, 1, 24, 22, 16] 1
3 [2, 24, 3, 24, 51] 0
4 [40, 1, 41, 18, 3] 1
我想创建另一列,并将值“Is Isogram”附加在“String”数组中,如下所示:
String Is Isogram IsoString
0 [47, 0, 49, 12, 46] 1 [47, 0, 49, 12, 46, 1]
1 [43, 50, 22, 1, 13] 1 [43, 50, 22, 1, 13, 1]
2 [10, 1, 24, 22, 16] 1 [10, 1, 24, 22, 16, 1]
3 [2, 24, 3, 24, 51] 0 [2, 24, 3, 24, 51, 0]
4 [40, 1, 41, 18, 3] 1 [40, 1, 41, 18, 3, 1]
我尝试使用带有 lambda 的 apply 函数:
df[''IsoString] = df.apply(lambda x: np.append(x['String'].values, x['Is Isogram'].values, axis=1))
但是它给了我一个我不太理解的 KeyError
KeyError: ('String', 'occurred at index String')
我该如何解决这个问题?
最佳答案
为 np.append
而不是 .apply
函数调用 axis=1
时出现问题:
df['IsoString'] = df.apply(lambda x: np.append(x['String'], x['Is Isogram']), axis=1)
更好/更快的是使用 numpy.hstack
如果 String
中每个列表的长度相同:
arr = np.hstack((np.array(df['String'].tolist()), df['Is Isogram'].values[:, None]))
print (arr)
[[47 0 49 12 46 1]
[43 50 22 1 13 1]
[10 1 24 22 16 1]
[ 2 24 3 24 51 0]
[40 1 41 18 3 1]]
df['IsoString'] = arr.tolist()
print (df)
String Is Isogram IsoString
0 [47, 0, 49, 12, 46] 1 [47, 0, 49, 12, 46, 1]
1 [43, 50, 22, 1, 13] 1 [43, 50, 22, 1, 13, 1]
2 [10, 1, 24, 22, 16] 1 [10, 1, 24, 22, 16, 1]
3 [2, 24, 3, 24, 51] 0 [2, 24, 3, 24, 51, 0]
4 [40, 1, 41, 18, 3] 1 [40, 1, 41, 18, 3, 1]
关于python - 基于数据框的其他列创建一个新的 pandas 数据框列,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59171537/