c# - 尝试统一使用 C# 从文本文件生成迷宫

Question

到目前为止，我可以从我的文本文件中读取。然后我继续尝试访问每一行。从这里我尝试访问行中的每个值。如果它是 1，我将在 x = 1 位置创建一个游戏对象，如果下一个是 1，则该对象将放置在 x = 2 位置。读取此行后，我想从 y = 0 更改位置(第一行)到 y=1 等等。

我的问题是，当我尝试运行它时，我似乎只能从每一行中获取第一个值。有人可以看看我的代码并告诉我我的脑残在哪里吗？我将不胜感激 :)!

//Splits each line to be accessed easily
            eachLine = File.ReadAllLines("Maze1.txt");

            //Gets number of lines
            int lines = File.ReadAllLines("Maze1.txt").Length;

            // Accesses each line one at a time
            foreach (string line in eachLine)
            {
                // Accessess each character in each line one at a time


            foreach(char c in line)
            {
                string currentNum = c.ToString();
                thisNum = Convert.ToInt32(currentNum);
                //Console.WriteLine("This Number: {0}",thisNum)

                    if (thisNum != 1)
                    {

                        //While i 
                        while(i < lines)
                        {
                            ObjectSpawnPosition = new Vector3(i+1,0,0);
                            Console.WriteLine("This num is 1");
                            Instantiate(obj, ObjectSpawnPosition, Quaternion.identity);
                            i++;
                        }
                    }

Answer 1

你的问题是你如何循环。如果你读到 1，你循环遍历行并为每一行创建一个对象。相反，您应该这样做:

int y = 0;

// Accesses each line one at a time
foreach (string line in eachLine)
{
    // reset the x position to the beginning of each line.
    int x = 0;

    // Accesses each character in each line one at a time
    foreach(char c in line)
    {
        string currentNum = c.ToString();
        thisNum = Convert.ToInt32(currentNum);

        if (thisNum == 1)
        {
            // Create a single object at x,y (no looping here)
            ObjectSpawnPosition = new Vector3(x,y,0);
            Instantiate(obj, ObjectSpawnPosition, Quaternion.identity);
        }
        // increment x inside the inner loop.
        x++;
    }
    // done with a line, so increment y to go to the next line.
    y++;
}