c# arrays 数组 b 的多个 3 个元素

Question

如何编写函数来获得新的 B 数组，但放入数组 A 的多个 3 个元素..

int[] a = new int[] {1,2,3,4,5,6,7,8,9,10};

b0 = a1,a2,a3
b1 = a4,a5,a6 
b2 = etc...

Answer 1

仅如果不允许您使用 Linq...

int[] a = new int[] {1,2,3,4,5,6,7,8,9,10};
int[,] b;
if(a.Length % 3 != 0)
{
    b = new int[a.Length/3+1,3];
}
else
{
    b = new int[a.Length/3, 3];
}

for(int i = 0; i< a.Length;i++)
{
    b[i/3,i%3] = a[i];
}