c# - 如何显式定义匿名方法符合什么签名？

Question

我声明了两个方法

public void MethodA(object o, Action<string> action) { }
public void MethodA(object o, Action<CustomType> action) { }

如何使用匿名方法调用这些函数？我知道我可以传递一个指向方法的指针，但我有兴趣使用匿名方法这样做吗？目前我收到错误消息“Ambitious call between...”

MethodA(this, c => { }); // how to explicitly say that C is of type CustomType?

Answer 1

MethodA(this, (CustomType c) => { });

或者如果您想将委托(delegate)类型显式声明为 Action<CustomType> :

MethodA(this, (Action<CustomType>)(c => { }));