C# - Xamarin 表单在切换时删除 ListView 项

Question

因此，我想删除我切换的 ListView 中的项目。我有一个这样的 ListView :

现在我希望当我单击要选择的内容时，它将从 ListView 中删除，但用户必须首先弹出提示，其中说明用户是否真的确定该项目是否可以删除.

这是我现在的代码:

private async void Switch_Toggled(object sender, ToggledEventArgs e)
        {
            Tasks task = (sender as Switch).BindingContext as Tasks;
            await ApiManager.UpdateTasksFromListAsync(task);
        }

这只是更新 API 上的一个值。但是我怎样才能从 ListView 中删除/隐藏它呢？

这是 xaml 代码:

<ListView x:Name="lvwDetailPage" SeparatorVisibility="None">
        <ListView.ItemTemplate>
            <DataTemplate>
                <ViewCell>
                    <Grid>
                        <Grid.ColumnDefinitions>
                            <ColumnDefinition Width="70" />
                            <ColumnDefinition />
                        </Grid.ColumnDefinitions>
                        <Grid.RowDefinitions>
                            <RowDefinition />
                        </Grid.RowDefinitions>

                        <Switch IsToggled="{Binding completed}" Grid.Column="0" Toggled="Switch_Toggled" />
                        <Label Grid.Column="1" Text="{Binding title}" TextColor="#212121" VerticalOptions="Center" Margin="10,0" />

                    </Grid>
                </ViewCell>
            </DataTemplate>
        </ListView.ItemTemplate>
    </ListView>

Answer 1

    ObservableCollection<Tasks> TaskList;

    private async Task GetData(long id)
    {
        List<Tasks> tasks = await ApiManager.GetTasksFromListAsync(id);

        TaskList = new ObservableCollection<Tasks>(tasks);

        lvwDetailPage.ItemsSource = TaskList;

        lvwDetailPage.ItemSelected += LvwDetailPage_ItemSelected;
    }

    private async void Switch_Toggled(object sender, ToggledEventArgs e)
    {
        Tasks task = (sender as Switch).BindingContext as Tasks;

        if (task != null)
        {
            await ApiManager.UpdateTasksFromListAsync(task);
            TaskList.Remove(task);
        }          
    }