c# - 我可以让我的继承类使用比这更少的代码获取父类实例的属性值吗？

Question

我需要单独的 Xml 序列化类。我想知道是否有更简单的方法让继承 BuildingDetail 类从父 Building 类获取属性值。

父类

public class Building
{
    public int BuildingId;
    public string BuildingName;

    protected Building()
    {
    }

    private Building(int buildingId, string buildingName)
    {
        BuildingId = buildingId;
        BuildingName = buildingName;
    }

    public static Building Load(int buildingId)
    {
        var dr = //DataRow from Database

        var building = new Building(
            (int) dr["BuildingId"],
            (string) dr["BuildingName"]);

        return building;
    }
}

继承类

public class BuildingDetail : Building
{
    public BaseList<Room> RoomList
    {
        get { return Room.LoadList(BuildingId); }
    }

    protected BuildingDetail()
    {
    }

    // Is there a cleaner way to do this?

    private BuildingDetail(int buildingId, string buildingName)
    {
        BuildingId = buildingId;
        BuildingName = buildingName;
    }

    public new static BuildingDetail Load(int buildingId)
    {
        var building = Building.Load(buildingId);

        var buildingDetail = new BuildingDetail(
            building.BuildingId, 
            building.BuildingName
            );

        return buildingDetail;
    }
}

谢谢。

Answer 1

首先，将基类构造函数访问修饰符更改为protected。然后你可以用 base 调用基类构造函数关键词:

 private BuildingDetail(int buildingId, string buildingName) 
     : base(buildingId, buildingName)
 {
     ...
 }

它将首先调用基础构造函数。此外，如果您不在构造函数之后放置 :base(param1, param2)，将调用基的空构造函数。