c# - 如何将 protobuf 序列化内容直接写入 SharpZipLib 流

Question

是否可以将 protobuf 序列化内容直接写入 SharpZipLib 流？当我尝试这样做时，看起来提供的流中没有填充来自 protobuf 的数据。稍后我需要从提供的 Zip 流中取回反序列化的实体。 我的代码如下所示:

private byte[] ZipContent(T2 content)
    {
        const short COMPRESSION_LEVEL = 4; // 0-9
        const string ENTRY_NAME = "DefaultEntryName";


        byte[] result = null;

        if (content == null)
            return result;

        IStreamSerializerProto<T2> serializer = this.GetSerializer(content.GetType());
        using (MemoryStream outputStream = new MemoryStream())
        {
            using (ZipOutputStream zipOutputStream = new ZipOutputStream(outputStream))
            {
                zipOutputStream.SetLevel(COMPRESSION_LEVEL);
                ZipEntry entry = new ZipEntry(ENTRY_NAME);
                entry.DateTime = DateTime.Now;
                zipOutputStream.PutNextEntry(entry);

                serializer.Serialize(zipOutputStream, content);
            }

            result = outputStream.ToArray();
        }

        return result;
    }

private class ProtobufStreamSerializer<T3> : IStreamSerializerProto<T3>
        {
            public ProtobufStreamSerializer()
            {
                ProtoBuf.Serializer.PrepareSerializer<T3>();
            }

    public void Serialize(Stream outputStream, T3 content)
    {
        Serializer.Serialize(outputStream, content);
    }

            public T3 Deserialize(Stream inputStream)
            {
                T3 deserializedObj;
                using (inputStream)
                {
                    deserializedObj = ProtoBuf.Serializer.Deserialize<T3>(inputStream);
                }
                return deserializedObj;
            }
        }

我正在尝试序列化的类示例:

[Serializable]
    [ProtoContract]
    public class Model
    {
        [XmlElement("ModelCode")]
        [ProtoMember(1)]
        public int ModelCode { get; set; }

                ...

    }

Answer 1

这就是问题所在，我相信(在问题的原始代码中):

public void Serialize(Stream outputStream, T3 content)
{
    using (var stream = new MemoryStream())
    {
        Serializer.Serialize(stream, content);
    }
}

您完全忽略了 outputStream，而是将数据写入一个新的 MemoryStream 然后被忽略。

我怀疑你只是想:

public void Serialize(Stream outputStream, T3 content)
{
    Serializer.Serialize(outputStream, content);
}

我还建议从您的 Deserialize 方法中删除 using 语句:我希望调用者负责处理输入流完成后。您的方法可以简化为:

public T3 Deserialize(Stream inputStream)
{
    return ProtoBuf.Serializer.Deserialize<T3>(inputStream);
}