c# - 转换到泛型时忽略 T

Question

我正试图减少一些额外的调用，并将 5 分钟的问题变成 30 分钟的问题。有没有办法在不知道泛型类型的情况下转换对象？在下面的代码中，我想制作 Complete<T, T2>简单 Complete<T2> .

public void Complete<T, T2>(object sender, RunWorkerCompletedEventArgs args) 
    where T2 : new()
{
    ServiceContainer<T, T2> callback = (ServiceContainer<T, T2>)args.Result;
    StateManager.BackgroundWorker result = (StateManager.BackgroundWorker)sender;
    callback.func(result.state, callback.response);
}

所以我希望它看起来像这样:

public void Complete<T2>(object sender, RunWorkerCompletedEventArgs args) 
    where T2 : new()
{
    ServiceContainer<object, T2> callback = (ServiceContainer<object, T2>)args.Result;
    StateManager.BackgroundWorker result = (StateManager.BackgroundWorker)sender;
    callback.func(result.state, callback.response);
}

Answer 1

您可以像这样使用动态语言运行时:

public void Complete<T2>(object sender, RunWorkerCompletedEventArgs args) 
    where T2 : new()
{
    dynamic callback = args.Result;
    dynamic result = sender;
    callback.func(result.state, callback.response);
}

如果您不在方法中使用 T2(就像在您的示例中那样)，您可以将其删除并使您的方法成为非通用方法。