我有一个ObservableCollection
即MobileList
类型的MobileModel
。 MobileModel的列表为MobileModelInfo
。
我只需要该MobileModelInfo
中的MobileList
。因此,我在方法ExtractFirstMobileList()
中使用了Linq Select语句。但是我无法分配列表,它显示了一个错误。
我的C#源代码:
public class Mobile
{
private ObservableCollection<MobileModel> _mobileList;
public ObservableCollection<MobileModel> MobileList
{
get { return _mobileList; }
set { _mobileList = value; OnPropertyChanged(); }
}
public void GetMobile()
{
List<MobileModel> mList = new List<MobileModel>();
List<MobileModelInfo> modList = new List<MobileModelInfo>();
MobileModel mob = new MobileModel();
modList.Clear();
mob.Brand = "Apple";
modList.Add(new MobileModelInfo { Name = "iPhone 4", Catagory = "Smart Phone", Year = "2011" });
modList.Add(new MobileModelInfo { Name = "iPhone 5", Catagory = "Smart Phone", Year = "2013" });
modList.Add(new MobileModelInfo { Name = "iPhone 6", Catagory = "Premium Smart Phone", Year = "2015" });
mob.Model = new ObservableCollection<MobileModelInfo>(modList);
mob.OS = "IOS";
mList.Add(mob);
mob = new MobileModel();
modList.Clear();
mob.Brand = "Samsung";
modList.Add(new MobileModelInfo { Name = "S4", Catagory = "Smart Phone", Year = "2011" });
modList.Add(new MobileModelInfo { Name = "S5", Catagory = "Smart Phone", Year = "2013" });
modList.Add(new MobileModelInfo { Name = "S6", Catagory = "Ultra Smart Phone", Year = "2015" });
mob.Model = new ObservableCollection<MobileModelInfo>(modList);
mob.OS = "Android";
mList.Add(mob);
mob = new MobileModel();
modList.Clear();
mob.Brand = "MicroSoft";
modList.Add(new MobileModelInfo { Name = "Lumina 9900", Catagory = "Phone", Year = "2011" });
modList.Add(new MobileModelInfo { Name = "Opera X220", Catagory = "Smart Phone", Year = "2013" });
mob.Model = new ObservableCollection<MobileModelInfo>(modList);
mob.OS = "Windows";
mList.Add(mob);
mob = new MobileModel();
modList.Clear();
mob.Brand = "Sony Ericssion";
modList.Add(new MobileModelInfo { Name = "S4", Catagory = "Smart Phone", Year = "2011" });
modList.Add(new MobileModelInfo { Name = "S5", Catagory = "Smart Phone", Year = "2013" });
modList.Add(new MobileModelInfo { Name = "S6", Catagory = "Ultra Smart Phone", Year = "2015" });
mob.Model = new ObservableCollection<MobileModelInfo>(modList);
mob.OS = "Android";
mList.Add(mob);
MobileList = new ObservableCollection<MobileModel>(mList);
ExtractFirstMobileList(MobileList);
}
public void ExtractFirstMobileList(ObservableCollection<MobileModel> Source)
{
List<MobileModelInfo> mInfo = Source.Select(t=> t.Model);
}
}
public class MobileModel : Notify
{
private string _brand = string.Empty;
private List<MobileModelInfo> _model = new List<MobileModelInfo>();
private string _os = string.Empty;
public string Brand
{
get { return _brand; }
set { _brand = value; OnPropertyChanged(); }
}
public List<MobileModelInfo> Model
{
get { return _model; }
set { _model = value; OnPropertyChanged(); }
}
public string OS
{
get { return _os; }
set { _os = value; OnPropertyChanged(); }
}
}
public class MobileModelInfo
{
public string Name { get; set; }
public string Catagory { get; set; }
public string Year { get; set; }
}
请协助我将Enumerable转换为首选类型。
最佳答案
如果要使用所有不同的MobileModelInfo
创建扁平化列表,则可以使用SelectMany
:
List<MobileModelInfo> mInfo = Source.SelectMany(t => t.Model).ToList();
但是您的方法称为
ExtractFirstMobileList
,它建议您要每个子列表中的第一项-在这种情况下,您可以使用:List<MobileModelInfo> mInfo = Source.Select(t => t.Model.First()).ToList();
希望这可以帮助
关于c# - 如何在C#中将Linq Select Enumerable转换为首选类型?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34524241/