c# - 反射排除基类的所有属性和所有其他派生类的特定属性

Question

我在下面有以下基类、中间类和派生类::

public class Base
{
    [DataMemberAttribute()]
    public int ValueBase { get; set; }

    [IgnoreForAllAttribute("Param1", "Param2")]
    public int IgnoreBase { get; set; }
}

public class Middle : Base
{
    [DataMemberAttribute()]
    public int ValueMiddle { get; set; }

    [IgnoreForAllAttribute("Param1", "Param2")]
    public int IgnoreMiddle { get; set; }
}

public class MostDerived : Middle
{
    [DataMemberAttribute()]
    public int ValueMostDerived { get; set; }

    [IgnoreForAllAttribute("Param1", "Param2")]
    public int IgnoreMostDerived { get; set; }
}

我需要一个给定类型的函数，我需要为层次结构中除基类之外的所有类返回 DataMemberAttribute 属性。

此外，图中的所有类都应忽略所有 IgnoreForAllAttribute 属性。

var derivedObject = new MostDerived();
var attributes = MyShinyAttributeFunction(derivedObject.GetType());
// returns [] { ValueMostDerived, ValueMiddle }

Answer 1

这是一个假定 DateMemberAttribute 和 IgnoreForAllAttribute 互斥的 LINQ 示例

IEnumerable<PropertyInfo> MyProperties(object o)
{
   o.GetType().GetProperties()
    .Where(p => !(p.DeclaringType is Base))
    .Where(p => p.GetCustomAttributes(false).Any(a => a is DataMemberAttribute)
}

假设属性不互斥的样本

IEnumerable<PropertyInfo> MyProperties(object o)
{
   o.GetType().GetProperties()
    .Where(p => !(p.DeclaringType is Base))
    .Where(p => 
       { 
          var attributes = p.GetCustomAttributes(false);
          return attributes.Any(a => a is DataMemberAttribute)
             && !attributes.Any(a => a is IgnoreForAllAttribute);
       }
}