public int Fibonacci(int x)
{
int prev = -1;
int next = 1;
for (int i = 0; i < x; i++)
{
int sum = prev + next;
prev = next;
next = sum;
Console.WriteLine(sum);
}
return sum; // plz teel me how can i return whole list ??
}
如何返回上述系列的全部输出?即如果 x=3 那么 0 1 1 2 那么我该如何返回它呢?
最佳答案
试试这个:
public IEnumerable<int> Fibonacci(int x)
{
int prev = -1;
int next = 1;
for (int i = 0; i < x; i++)
{
int sum = prev + next;
prev = next;
next = sum;
yield return sum;
}
}
关于c# - 我怎样才能退回斐波那契数列?我应该使用 IList<> 吗?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/4564472/