我打算在 C# 中使用 OleDbDataAdapter 在 Access 数据库中插入数据,但我收到一条错误消息 INSERT INTO 命令中的语法错误
BackgroundWorker worker = new BackgroundWorker();
OleDbDataAdapter dbAdapter new OleDbDataAdapter();
OleDbConnection dbConnection = new OleDbConnection("Provider=Microsoft.Jet.OLEDB.4.0;Data Source=E:\\PMS.mdb");
worker = new BackgroundWorker();
worker.WorkerReportsProgress = true;
worker.DoWork += InsertJob;
worker.ProgressChanged += InsertJobCompleted;
worker.RunWorkerAsync(args);
InsertJob 函数是:
private void InsertJob(object sender, DoWorkEventArgs e)
{
var args = (InsertJobArgs)e.Argument;
try
{
dbAdapter.SelectCommand = new OleDbCommand("SELECT * FROM Sheet", dbConnection);
dbAdapter.Fill(args.DataTable);
var builder = new OleDbCommandBuilder(dbAdapter);
var row = args.DataTable.NewRow();
row["UserName"] = args.Entry.UserName;
row["Password"] = args.Entry.Password;
args.DataTable.Rows.Add(row);
dbAdapter.InsertCommand = builder.GetInsertCommand();
dbAdapter.Update(args.DataTable);
builder.Dispose();
}
catch (Exception ex)
{
args.Exception = ex;
worker.ReportProgress(0, args);
return;
}
worker.ReportProgress(100, args);
}
我收到在线错误:dbAdapter.Update(args.DataTable);
我尝试用 visual studio 调试它,发现所有 InsertCommand 参数值都是 null
我尝试在调用 dbAdapter.Update(args.DataTable);
dbAdapter.InsertCommand.Parameters[0].Value = args.Entry.UserName;
dbAdapter.InsertCommand.Parameters[1].Value = args.Entry.Password;
最佳答案
试试这个:
紧接在行之后
var builder = new OleDbCommandBuilder(dbAdapter);
添加两行
builder.QuotePrefix = "[";
builder.QuoteSuffix = "]";
这将告诉 OleDbCommandBuilder
将表名和列名括在方括号中,生成如下所示的 INSERT 命令
INSERT INTO [TableName] ...
而不是默认形式
INSERT INTO TableName ...
如果任何表名或列名包含空格或“有趣”字符,或者它们恰好是 Access SQL 中的保留字,则需要方括号。 (在你的情况下,我怀疑你的表有一个名为 [Password] 的列,并且 PASSWORD
是 Access SQL 中的保留字。)
关于c# - 使用 OleDbCommandBuilder 时 Access SQL 语法错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32020070/