c# - 从 JSON post 返回成功消息

Question

我有以下内容可以将 JSON 发布到 C# Web API:

submitForm(data: any): Observable<Response> {
    return this.http.post(
        'https://localhost:44396/api/PostNewComputer/AddItem/?=', data,
        { headers: new Headers({ 'Content-Type': 'application/x-www-form-urlencoded' }) }).subscribe(data => { return "test"; });
}

API Controller :

public class PostNewComputerController : ApiController
    {
        [HttpPost]
        public IHttpActionResult AddItem(HttpRequestMessage request)
        {

            //var dynamicObject = Json.Decode(jsonString);
            var jsonString = request.GetQueryNameValuePairs();

            string message;

            using (SqlConnection con = new SqlConnection("data source = MYSERVER; initial catalog = AssetDB; integrated security = SSPI; persist security info = True; Trusted_Connection = Yes"))
            {
                using (SqlCommand cmd = new SqlCommand("POST_NEW_COMPUTER", con) { CommandType = CommandType.StoredProcedure })
                {
                    try
                    {
                        cmd.Parameters.Add(new SqlParameter("@JSON_TEXT", SqlDbType.NVarChar)).Value = jsonString;

                        con.Open();
                        cmd.ExecuteNonQuery();

                        con.Close();

                        message = "Item Successfully Added";
                    }
                    catch (Exception e)
                    {
                        //throw e;
                        message = e.Message;
                    }

                }

                return Ok(message);
            }
        }
    }

我正在尝试从 POST 调用创建一条响应消息，然后在用户提交表单时将其反馈到网页以表明该帖子已生效。

但是，当前的设置不起作用，我正在努力解决这个问题。

是否有正确的方法来正确执行此操作？

Answer 1

使用 HttpResponseMessage 回传消息为:

[HttpPost]
[ResponseType(typeof(string))]
public HttpResponseMessage AddItem(HttpRequestMessage request)
{
    HttpResponseMessage response = null;
    string message = string.Empty;

    try 
    {
        .....

        message = "Item Successfully Added";
    }
    catch (Exception e)
    {
        .....

        message = e.Message;
    }

    response = Request.CreateResponse<string>(HttpStatusCode.OK, message);
    return response;
}