c# - 将 Python 数组转换为 C# 并返回值

Question

我正在将 Python 脚本转换为 C#，我需要一些帮助。我真的没有任何 Python 经验。这些类型的数组对我来说是全新的。

倒数第二行 var posVec = dSorted[0][1]; 以及最后一行:return posVec;.

var posVec 的实际变量类型是什么？

我还试图返回 posVec，它应该是一个 Vector3d，但我收到了这个错误:

Cannot implicitly convert type 'double' to 'Rhino.Geometry.Vector3d'

我做错了什么？ 谢谢!

python :

posVec = dSorted[0][1]
return posVec

完整的 Python 方法:

def getDirection(self):
    #find a new vector that is at a 90 degree angle

    #define dictionary
    d = {}
    #create an list of possible 90 degree vectors
    arrPts = [(1,0,0), (-1,0,0), (0,1,0), (0,-1,0)]
    vec = self.vec
    vec = rs.VectorUnitize(vec)

    #find the distance between the self vec
    #position and one of the 4 90 degree vectors
    #create a dictionary that matches the distance with the 90 degree vector
    for i in range(4):
        dist = rs.Distance(vec, arrPts[i])
        d[dist] = arrPts[i]
    #sort the dictionary.  This function converts it to an array
    #sort by the distances, "value"/item 0
    dSorted = sorted(d.items(), key=lambda value: value[0])

    #select the second item in the array which is one of the 90 degree vectors
    posVec = dSorted[0][1]
    return posVec

到目前为止我重写的完整 C# 方法:

    // find a new vector that is at a 90 degree angle
    public Vector3d GetDirection()
    {
        // define dictionary
        Dictionary<double, Vector3d> d = new Dictionary<double, Vector3d>();

        Vector3d[] arrPts = new Vector3d[] {
            new Vector3d(1, 0, 0),
            new Vector3d(-1, 0, 0),
            new Vector3d(0, 1, 0),
            new Vector3d(0, -1, 0),
            new Vector3d(0, 0, 1),
            new Vector3d(0, 0, -1) };

        _vec = Vec;
        _vec.Unitize();

        // find the distance between the self vec position and one of the 6 90 degree vectors
        // create a dictionary that matches the distance with the 90 degree vector

        for (int i = 0; i < arrPts.Length; i++)
        {
            double dist = Math.Sqrt(
                ((_vec.X - arrPts[i].X) * (_vec.X - arrPts[i].X)) +
                ((_vec.Y - arrPts[i].Y) * (_vec.Y - arrPts[i].Y)) +
                ((_vec.Z - arrPts[i].Z) * (_vec.Z - arrPts[i].Z)));

            d.Add(dist, arrPts[i]);
        }

        Vector3d[] dSorted = d.Values.ToArray();
        var posVec = dSorted[0][1];
        return posVec;
    }

Answer 1

我参加聚会迟到了，但不管怎样，如果它在未来为某人服务......

您正在根据 dictionary(d) 的值创建一个 Vector3d(dSorted) 数组，但您尝试将其转换为 var posVec 应该是使用 dSorted[0][1] 的 Vector3d。这是锯齿状数组的表示法，但您将 dSorted 声明为 Vector3d 的数组。

因此，要访问其中一项，只需使用 dSorted[0]。