c# - 替换 PL/SQL 中的特殊 XML 字符

Question

我正在使用返回特殊字符的 SQL XMLAgg 函数。我需要用“常规”字符替换它们，即替换 <至 <等..

我试过使用UTL_I18N.UNESCAPE_REFERENCE但我遇到了错误

ORA-22835: Buffer too small for CLOB or BLOC to RAW conversion (actual: 10030, maximum: 4000)

我的查询看起来像:UTL_I18N.UNESCAPE_REFEREENCE(xmlagg(xmlelement(e, comments)).extract('//text()').getclobval))

我该怎么做？

谢谢

Answer 1

像这样以 block 的形式处理 CLOB:

CREATE OR REPLACE FUNCTION UNESCAPE_XML(xml_clob IN CLOB) RETURN CLOB IS
DECLARE

    clob_UNESCAPE CLOB;    
    read_offset INTEGER := 1;
    ClobLen INTEGER;
    amount INTEGER := 3000;

BEGIN

    ClobLen := DBMS_LOB.GETLENGTH(xml_clob);
    DBMS_LOB.CREATETEMPORARY(clob_UNESCAPE, TRUE);
    LOOP
        EXIT WHEN read_offset > ClobLen;
        stringBuffer := UTL_I18N.UNESCAPE_REFEREENCE(DBMS_LOB.SUBSTR(xml_clob , amount, read_offset));
        DBMS_LOB.WRITEAPPEND(clob_UNESCAPE, LENGTH(stringBuffer), stringBuffer);
        read_offset := read_offset + amount;
    END LOOP;

    RETURN clob_UNESCAPE;
END;