所以这个函数是在更大的位图中找到一个位图..buuuut..它需要 4-6 秒才能通过 1920x1080 屏幕.. 我不会问你我是否 100% 理解该代码,我不知道,我是编程的新手,我的逻辑已经有点睡着了(凌晨 4:00)..(代码来自视频教程,我是甚至没有研究它就使用了很长时间 :D)
所以我真正想要的是让机器人在游戏中寻找像素/图片然后点击它,但是 4-6 秒太长了,不是吗?我对此很好奇,因为用其他编程语言制作的几款游戏的像素机器人非常非常快!比如1s... 所以我想,它是由 c# 引起的吗?它可能不是由 c# 引起的 .. 但这段代码很有效,但也许不需要那么长? 我考虑过“获得更快的循环”.. 但那可能不会发生。
尝试发明一些解决方案,我将不胜感激!而且我仍然认为这个问题对于其他许多人来说可能很重要。
private bool FindBitmap(Bitmap bmpNeedle, Bitmap bmpHaystack, out Point location)
{
for (int outerX = 0; outerX < bmpHaystack.Width - bmpNeedle.Width; outerX++)
{
for (int outerY = 0; outerY < bmpHaystack.Height - bmpNeedle.Height; outerY++)
{
for (int innerX = 0; innerX < bmpNeedle.Width; innerX++)
{
for (int innerY = 0; innerY < bmpNeedle.Height; innerY++)
{
Color cNeedle = bmpNeedle.GetPixel(innerX, innerY);
Color cHaystack = bmpHaystack.GetPixel(innerX + outerX, innerY + outerY);
if (cNeedle.R != cHaystack.R || cNeedle.G != cHaystack.G || cNeedle.B != cHaystack.B)
{
goto notFound;
}
}
}
location = new Point(outerX, outerY);
return true;
notFound:
continue;
}
}
location = Point.Empty;
return false;
}
最佳答案
我使用LockBits 和不安全 代码为其编写了一个小类。 表现很棒。 我决定使用 uint 值而不是颜色。 对于转换,您可以使用 http://www.vcskicks.com/color-uint.php
/// <summary>
/// Represents a bitmap with bit functions.
/// </summary>
public class LockedBitmap
{
private Rectangle _bounds;
/// <summary>
/// Gets or sets the bitmap.
/// </summary>
public Bitmap Bitmap { get; set; }
/// <summary>
/// Gets or sets the values of the bitmap.
/// </summary>
/// <remarks>Watch at the static length!</remarks>
public uint[] Buffer { get; set; }
/// <summary>
/// Gets or sets the bitmap data.
/// </summary>
public BitmapData BitmapData { get; set; }
/// <summary>
/// Initializes a new instance of <see cref="LockedBitmap" />.
/// </summary>
/// <param name="bitmap">The processed bitmap.</param>
public LockedBitmap(Bitmap bitmap)
{
this.Bitmap = bitmap;
}
/// <summary>
/// Locks a Bitmap into system memory.
/// </summary>
public unsafe void LockBits()
{
var width = this.Bitmap.Width;
var height = this.Bitmap.Height;
var imageLockMode = ImageLockMode.UserInputBuffer;
// Setting imageLockMode
imageLockMode = imageLockMode | ImageLockMode.ReadOnly;
imageLockMode = imageLockMode | ImageLockMode.WriteOnly;
// Save the bouunds
this._bounds = new Rectangle(0, 0, width, height);
// Create Pointer
var someBuffer = new uint[width*height];
// Pin someBuffer
fixed (uint* buffer = someBuffer) //pin
{
// Create new bitmap data.
var temporaryData = new BitmapData
{
Width = width,
Height = height,
PixelFormat = PixelFormat.Format32bppArgb,
Stride = width*4,
Scan0 = (IntPtr) buffer
};
// Get the data
this.BitmapData = this.Bitmap.LockBits(this._bounds, imageLockMode, PixelFormat.Format32bppArgb,
temporaryData);
// Set values
this.Buffer = someBuffer;
}
}
/// <summary>
/// Unlocks this Bitmap from system memory.
/// </summary>
public void UnlockBits()
{
this.Bitmap.UnlockBits(this.BitmapData);
}
/// <summary>
/// Iterate through all pixel values.
/// </summary>
public unsafe void Iterate()
{
// Dimension
var width = this.Bitmap.Width;
var height = this.Bitmap.Height;
// Actual uint position
int cp = 0;
// Pointer at the fist uint
var scp = (uint*)this.BitmapData.Scan0;
// Stick the array
fixed (uint* cb = this.Buffer)
// Step through each pixel
for (uint* cbp = cb, cbdest = cb + this.Buffer.Length; cbp < cbdest; cbp++)
{
// Get x and y from position
var x = cp % width;
var y = cp / width;
var color = *cbp;
cp++; // Increment cp
}
}
}
示例用法:
using (OpenFileDialog ofd = new OpenFileDialog())
{
if (ofd.ShowDialog() == DialogResult.OK)
{
Image image = Image.FromFile(ofd.FileName);
LockedBitmap locked = new LockedBitmap((Bitmap) image);
locked.LockBits();
locked.Iterate();
locked.UnlockBits();
}
}
color 现在具有像素颜色的值。 cp 是绝对位置 (1D) 和 (x|y) 点在位图中的位置 (2D)
关于c# - 在更大的位图中查找位图(Pixel bot)-如何使其/for循环更快?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25467926/