C# JSON 解析问题

Question

大家好，我目前正在做最后一年的项目，快结束了。然而，我被困在一件小事上，它在 C# 中解析下面的 JSON 字符串。

我的错...复制并粘贴了 JSON 文件的摘录。这是我检查 jsonutils.org 时有效的整个 JSON 字符串

{ 
    "activities-steps" : [ 
        { 
            "dateTime" : "2016-02-10",
            "value" : "2624"
        } 
    ],
    "activities-steps-intraday" : { 
        "dataset" : [ 
        { 
            "time" : "00:00:00",
            "value" : 0
        },
        { 
            "time" : "00:01:00",
            "value" : 0
        },
        { 
            "time" : "00:02:00",
            "value" : 0
        },
        { 
            "time" : "00:03:00",
            "value" : 0
        },
        { 
            "time" : "00:04:00",
            "value" : 0
        },
        { 
            "time" : "00:05:00",
            "value" : 0
        },
        { 
            "time" : "00:06:00",
            "value" : 0
        },
        { 
            "time" : "00:07:00",
            "value" : 0
        },
        { 
            "time" : "00:08:00",
            "value" : 0
        },
        { 
            "time" : "00:09:00",
            "value" : 0
        },
        { 
            "time" : "00:10:00",
            "value" : 0
        },
        { 
            "time" : "00:11:00",
            "value" : 0
        },
        { 
            "time" : "00:12:00",
            "value" : 0
        },
        { 
            "time" : "00:13:00",
            "value" : 0
        },
        { 
            "time" : "00:14:00",
            "value" : 0
        },
        { 
            "time" : "00:15:00",
            "value" : 0
        },
        { 
            "time" : "00:16:00",
            "value" : 0
        },
        { 
            "time" : "00:17:00",
            "value" : 0
        }
        ],
        "datasetInterval" : 1,
        "datasetType" : "minute"
    }
}

我需要第一个 JSON 对象中的 dateTime 值，然后是第二个对象中的时间和值项的值。我已经实现了下面的代码，但是它一直给我一个 NullReferenceException。

这些方法用于帮助解析 JSON 对象

public class RootObject
{
    public Activity activity { get; set; }
    public ActivityGranular activity_granular { get; set; }
}

public class Activity
{
    public string dateTime { get; set; }
    public string value { get; set; }
}

 public class ActivityGranular
{
    public List<ActivityGranularDatapoint> dataset { get; set; }
    public int datasetGranularity { get; set; }
    public string datasetGranularityType { get; set; }
}

public class ActivityGranularDatapoint
{
    public string time { get; set; }
    public int value { get; set; }
}

主类中的 MainCode 执行时在上面的根对象类中的两个根元素中返回 null 并给出一个 NullReferenceExceptions

resultsJSON.Replace("-", "_");

root = JsonConvert.DeserializeObject<RootObject>(resultsJSON);

activity = root.activites_steps;
activityGranular = root.activities_steps_intraday;

for (int a = 0; a < activityGranular.dataset.Count; a++)
{
    activityGranularDatapoint[a].time = activityGranular.dataset[a].time;
   activityGranularDatapoint[a].value = activityGranular.dataset[a].value;
}

非常感谢所有帮助:)

Answer 1

如果您的 json 中的属性名称不符合您的需要，只需使用 JsonProperty 属性。只是不要使用:

• 解决或破解 json 数据。
• 不替换json的任何内容
• 顺其自然。

下面的代码只是通过如下重命名类的属性来工作

public class RootObject
{
    [JsonProperty("activities-steps")]
    public List<Activity> ActivitesSteps { get; set; }

    [JsonProperty("activities-steps-intraday")]
    public ActivityGranular ActivitiesStepsIntraday { get; set; }
}

public class Activity
{
    [JsonProperty("dateTime")]
    public string DateTime { get; set; }

    [JsonProperty("value")]
    public string Value { get; set; }
}

public class ActivityGranular
{
    [JsonProperty("dataset")]
    public List<ActivityGranularDatapoint> DataSet { get; set; }

    [JsonProperty("datasetInterval")]
    public int DatasetInterval { get; set; }

    [JsonProperty("datasetType")]
    public string DatasetType { get; set; }
}

public class ActivityGranularDatapoint
{
    [JsonProperty("time")]
    public string Time { get; set; }

    [JsonProperty("value")]
    public int Value { get; set; }
}