c# - 如何在目标阈值内简化图像停止运动

Question

我已经尝试过向其他人解释我要做什么，但失败得很惨。因此，如果您不介意的话，我将只向您展示代码并尝试稍微解释一下。

        if (MovePetMoving)
        {
            if (MovePetSlope[0] > 0)
            {
                if (MovePetSlope[1] > 0 && Convert.ToDouble(pictureBoxPet.Location.X) + MovePetSlope[0] <= MovePetTarget[0] && Convert.ToDouble(pictureBoxPet.Location.Y) + MovePetSlope[1] <= MovePetTarget[1])
                {
                    MovePetWorker(pictureBoxPet, pictureBoxPet.Location.X + MovePetSlope[0], pictureBoxPet.Location.Y + MovePetSlope[1]);
                    //MsgBox("MovePetSlope[0] > 0 and MovePetSlope[1] > 0", "");
                }
                else if (MovePetSlope[1] < 0 && Convert.ToDouble(pictureBoxPet.Location.X) + MovePetSlope[0] <= MovePetTarget[0] && Convert.ToDouble(pictureBoxPet.Location.Y) + MovePetSlope[1] >= MovePetTarget[1])
                {
                    MovePetWorker(pictureBoxPet, pictureBoxPet.Location.X + MovePetSlope[0], pictureBoxPet.Location.Y + MovePetSlope[1]);
                    //MsgBox("MovePetSlope[0] > 0 and MovePetSlope[1] < 0", "");
                }
                else
                {
                    MovePetMoving = false;
                    //MsgBox("Error", "");
                }
            }
            else if (MovePetSlope[0] < 0)
            {
                if (MovePetSlope[1] > 0 && Convert.ToDouble(pictureBoxPet.Location.X) + MovePetSlope[0] >= MovePetTarget[0] && Convert.ToDouble(pictureBoxPet.Location.Y) + MovePetSlope[1] <= MovePetTarget[1])
                {
                    MovePetWorker(pictureBoxPet, pictureBoxPet.Location.X + MovePetSlope[0], pictureBoxPet.Location.Y + MovePetSlope[1]);
                    //MsgBox("MovePetSlope[0] < 0 and MovePetSlope[1] > 0", "");
                }
                else if (MovePetSlope[1] < 0 && Convert.ToDouble(pictureBoxPet.Location.X) + MovePetSlope[0] >= MovePetTarget[0] && Convert.ToDouble(pictureBoxPet.Location.Y) + MovePetSlope[1] >= MovePetTarget[1])
                {
                    MovePetWorker(pictureBoxPet, pictureBoxPet.Location.X + MovePetSlope[0], pictureBoxPet.Location.Y + MovePetSlope[1]);
                    //MsgBox("MovePetSlope[0] < 0 and MovePetSlope[1] < 0" + Convert.ToString(pictureBoxPet.Location.X) + MovePetSlope[0] + MovePetTarget[0], "");
                }
                else
                {
                    MovePetMoving = false;
                    //MsgBox("Error", "");
                }
            }
        }

    }

就是这样。如果您想知道所有对“宠物”的引用是什么，我正在为我的小妹妹制作一个 tamogotchi(或者无论您如何拼写)之类的游戏。

我遇到的问题是 MovePetSlope[1] 或 [0] 的值可以是正值也可以是负值。我提出了一些适用于正值但不适用于负值的比较。我相信在目前的状态下，它根本不起作用。

如有任何帮助，我们将不胜感激。

提前致谢!

Answer 1

尝试使用 Math.Abs​​ 来简化您的比较。 一般来说，宠物应该一直 move 直到Math.Abs(pictureBoxPet.Location.X-MovePetTarget[0]) < Math.Abs(MovePetSlope[0])。 Y 和 1 也类似。您最终应该得到很多更简单的代码。

如果您的宠物直接朝目标 move ，这应该可以解决问题:

if (MovePetMoving)
{
    if (Math.Abs(pictureBoxPet.Location.X-MovePetTarget[0]) < Math.Abs(MovePetSlope[0]))
        MovePetMoving = false;
    else
        MovePetWorker(pictureBoxPet, pictureBoxPet.Location.X + MovePetSlope[0], pictureBoxPet.Location.Y + MovePetSlope[1]);
}