在 WCF REST API 中,出于某种原因,我想设置自己的 StatusCode -
WebOperationContext.Current.OutgoingResponse.StatusCode = HttpStatusCode.Forbidden (or any other statuscode)
它根本不像在客户端那样工作:-
using (HttpWebResponse restResponse = (HttpWebResponse)restRequest.GetResponse())
{
if (restResponse.StatusCode != HttpStatusCode.OK)
{
retVal = String.Format("Request failed. Received HTTP {0}, Description : {1}", restResponse.StatusCode, restResponse.StatusDescription);
return retVal;
}
using (var st = restResponse.GetResponseStream())
{
StreamReader sr = new StreamReader(st);
retVal = sr.ReadToEnd();
return retVal;
}
}
但这里的restResponse.StatusCode始终是HttpStatusCode.OK。
我可以知道原因吗?这里出了什么问题?
添加:-
我尝试在休息服务方法中使用以下内容 -
throw new WebFaultException<string>(<...Your message....>, HttpStatusCode.Forbidden );
但这种方法的问题是在客户端......它使代码出来
Try
{
using (HttpWebResponse restResponse = (HttpWebResponse)restRequest.GetResponse())
{
if (restResponse.StatusCode != HttpStatusCode.OK)
{
retVal = String.Format("Request failed. Received HTTP {0}, Description : {1}", restResponse.StatusCode, restResponse.StatusDescription);
return retVal;
}
using (var st = restResponse.GetResponseStream())
{
StreamReader sr = new StreamReader(st);
retVal = sr.ReadToEnd();
return retVal;
}
}
}
catch
{
//it comes here when using "throw new WebFaultException...."
}
没有必要使用--
retVal = String.Format("Request failed. Received HTTP {0}, Description : {1}", restResponse.StatusCode, restResponse.StatusDescription);
return retVal;
有什么建议吗?
最佳答案
在 WCF Rest API 中,您可以使用它
throw new WebFaultException<string>(<...Your message....>, HttpStatusCode.Forbidden );
关于c# - WebOperationContext.Current.OutgoingResponse.StatusCode 不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18644977/