使用此代码:
private void menuItem2_Click(object sender, System.EventArgs e)
{
String xmlFile = "DuckbilledPlatypiGuy.xml";
String uri = "http://192.168.125.50:21608/api/inventory/sendXML/duckbill/platypus/testfyle";
RESTfulMethods rm = new RESTfulMethods();
rm.SendXMLFile(xmlFile, uri, 500);
}
public void SendXMLFile(string xmlFilepath, string uri, int timeout)
{
StringBuilder sb = new StringBuilder();
using (StreamReader sr = new StreamReader(xmlFilepath))
{
. . .
...我收到“找不到文件 '\DuckbilledPlatypiGuy.xml'”
为什么它要在文件名前面加上一个反引号?这是问题所在吗?如果是,我该如何预防?
该文件与 .exe 位于同一文件夹中,因此应该显而易见。
更新
我尝试过这个:
String xmlFile = "\\DuckbilledPlatypiGuy.xml";
...但这没有什么区别 - 仍然得到,“找不到文件'\DuckbilledPlatypiGuy.xml'”所以无论我给文件名没有敲击或两次,它似乎仍然我认为它有一个。
还尝试了以下方法,结果相同:
String xmlFile = @"DuckbilledPlatypiGuy.xml";
更新2
在我的 .NET Compact Framework 书中(第 338 页,Andy Wigley 撰写的书)中找到此内容后:
StreamReader myReader = new StreamReader("\\myFile.txt");
...我尝试过这个:
using (StreamReader sr = new StreamReader("\\" + xmlFilepath))
...甚至这个:
using (StreamReader sr = new StreamReader("\\DuckbilledPlatypiGuy.xml"))
...但我仍然收到相同的错误消息。
更新3
如果我这样做:
String fallName = String.Format("\\{0}", xmlFilepath);
MessageBox.Show(String.Format("fallName is {0}", fallName));
using (StreamReader sr = new StreamReader(fallName))
...我看到“fallName is '\DuckbilledPlatypiGuy.xml'”,并且收到相同的旧错误消息。
如果我这样做(似乎期望在文件名前面加上双倍的回击):
String fallName = String.Format("\\\\{0}", xmlFilepath);
MessageBox.Show(String.Format("fallName is {0}", fallName));
using (StreamReader sr = new StreamReader(fallName))
...我看到“fallName is '\DuckbilledPlatypiGuy.xml'”,然后收到 IOException。那么文件名最终被接受(在 IO 异常之前)?奇怪......或者这里有其他东西在起作用?
更新4
在那之后我根本就没有走得太远 - 我什至从来没有看到过用这段代码“Made it point 1”:
public void SendXMLFile(string xmlFilepath, string uri, int timeout) // timeout should be 500
{
StringBuilder sb = new StringBuilder();
MessageBox.Show(String.Format("xmlFilepath is {0}", xmlFilepath));
String fallName = String.Format("\\\\{0}", xmlFilepath);
MessageBox.Show(String.Format("fallName is {0}", fallName));
using (StreamReader sr = new StreamReader(fallName))
{
String line;
while ((line = sr.ReadLine()) != null)
{
sb.Append(line);
sb.Append("\r\n");
}
}
MessageBox.Show("Made it to point 1");
string strData = @sb.ToString();
strData = strData.Replace("\"", "'");
string body = String.Format("\"{0}\"", strData);
MessageBox.Show("Made it to point 2");
CreateRequestNoCredentials(uri, HttpMethods.POST, body, "application/json");
MessageBox.Show("Made it to point 3");
}
更新5
好的,将文件访问代码更改为以下内容(从“我的文档”文件夹中获取文件,而不是从 .exe 所在的文件夹中获取文件):
StreamReader sr = new StreamReader(@"\My Documents\desktop.ini");
...允许我避免错误消息,但我仍然没有到达服务器中的断点。
整个代码是:
private void menuItem2_Click(object sender, System.EventArgs e)
{
String xmlFile = "DuckbilledPlatypiGuy.xml";
String uri = "http://192.168.125.50:21608/api/inventory/sendXML/duckbill/platypus/testfyle";
RESTfulMethods rm = new RESTfulMethods();
rm.SendXMLFile(xmlFile, uri, 500);
}
public void SendXMLFile(string xmlFilepath, string uri, int timeout) // timeout should be 500
{
StringBuilder sb = new StringBuilder();
StreamReader sr = new StreamReader(@"\My Documents\desktop.ini");
String line;
while ((line = sr.ReadLine()) != null)
{
sb.Append(line);
sb.Append("\r\n");
}
sr.Close();
MessageBox.Show("Made it to point 1");
string strData = @sb.ToString();
strData = strData.Replace("\"", "'");
string body = String.Format("\"{0}\"", strData);
MessageBox.Show("Made it to point 2");
CreateRequestNoCredentials(uri, HttpMethods.POST, body, "application/json");
MessageBox.Show("Made it to point 3");
}
public HttpWebRequest CreateRequestNoCredentials(string uri, HttpMethods method, string data, string contentType)
{
WebRequest request = WebRequest.Create(uri);
request.Method = Enum.ToObject(typeof(HttpMethods), method).ToString();
request.ContentType = contentType;
((HttpWebRequest)request).Accept = contentType;
((HttpWebRequest)request).KeepAlive = false;
((HttpWebRequest)request).ProtocolVersion = HttpVersion.Version10;
if (method != HttpMethods.GET && method != HttpMethods.DELETE)
{
byte[] arrData = Encoding.UTF8.GetBytes(data);
request.ContentLength = arrData.Length;
using (Stream oS = request.GetRequestStream())
{
oS.Write(arrData, 0, arrData.Length);
}
}
else
{
// If we're doing a GET or DELETE set ContentLength to zilch
request.ContentLength = 0;
}
return request as HttpWebRequest;
}
服务器代码这样装饰:
[Route("api/inventory/sendXML/{userId}/{pwd}/{filename}")]
...未达到/未命中断点。
更新6
cookies 的关键是在命令提示符下添加以下内容:
netsh http add urlacl url=http://shannon2:80/ user=everyone
...或者这个:
netsh http add urlacl url=http://shannon2:8080/ user=everyone
请参阅更新 5 here了解更多详情
最佳答案
尝试像这样映射路径:
string appPath = Application.StartupPath;
string filePath = "DuckbilledPlatypiGuy.xml";
string fullpath = Path.Combine(appPath, filePath);
关于c# - 为什么我得到 "could not find file '\[文件名 ]'"?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25857681/