我想要一个按钮来显示应用程序设置窗口,如下所示:
<Window.Resources>
<local:SettingsWindow x:Key="SettingsWnd"/>
</Window.Resources>
<Window.DataContext>
<local:MyViewModel/>
</Window.DataContext>
<Button Command="{Binding ShowSettingsCommand}"
CommandParameter="{DynamicResource SettingsWnd}"/>
ViewModel 有点东西:
class MyViewModel : BindableBase
{
public MyViewModel()
{
ShowSettingsCommand = new DelegateCommand<Window>(
w => w.ShowDialog());
}
public ICommand ShowSettingsCommand
{
get;
private set;
}
}
问题是它只能工作一次,因为您无法重新打开以前关闭的窗口。显然,上面的 XAML 不会像这样打开新实例。
有没有办法在每次调用命令时将新窗口作为 CommandParameter
传递?
最佳答案
这个转换器能解决您的问题吗?
class InstanceFactoryConverter : IValueConverter
{
public object Convert(object value, Type targetType, object parameter, CultureInfo culture)
{
var type = value.GetType();
return Activator.CreateInstance(type);
}
public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture)
{
throw new NotImplementedException();
}
}
...
<Window.Resources>
<local:SettingsWindow x:Key="SettingsWnd"/>
<local:InstanceFactoryConverter x:Key="InstanceFactoryConverter"/>
</Window.Resources>
...
<Button Command="{Binding ShowSettingsCommand}"
CommandParameter="{Binding Source={StaticResource SettingsWnd}, Converter={StaticResource InstanceFactoryConverter}}"/>
关于c# - 每次新窗口作为命令参数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31950480/