c# - 比较两个复杂的列表对象

标签 c# linq

如何检查两个对象列表是否相同?我有具有相同结构的列表 A 和列表 B:

[XmlRoot(ElementName = "Details")]
public class Details
{
    [XmlElement(ElementName = "time")]
    public string time { get; set; }
    [XmlElement(ElementName = "duration")]
    public string duration { get; set; }
}

[XmlRoot(ElementName = "Remark")]
public class Remark
{
    [XmlElement(ElementName = "RemarkText")]
    public string RemarkText { get; set; }
    [XmlElement(ElementName = "isRemarkVisible")]
    public Boolean IsRemarkVisible { get; set; }
}

[XmlRoot(ElementName = "test")]
public class test
{
    [XmlElement(ElementName = "ID")]
    public string ID { get; set; }
    [XmlElement(ElementName = "Name")]
    public string Name { get; set; }
    public Details Details { get; set; }
    [XmlElement(ElementName = "Remark")]
    public Remark Remark { get; set; }
}

[XmlRoot(ElementName = "Tests")]
public class Tests
{
    [XmlElement(ElementName = "test")]
    public test[] test { get; set; }
}

我使用 linq 将其转换为列表。

列表A:

Test
id=1
name=abc
details
    starttime=9.00
    endtime=12.00
    duration=1hr
Remark
    RemarkText= remark1 
    IsRemarkVisible=true

列表B:

Test
id=1
name=abc
details
    starttime=9.00
    endtime=12.00
    duration=1hr
Remark
    RemarkText= remark2 
    IsRemarkVisible=true

这里两个列表不相同(remarkText 字段)。我想要一段代码来比较这两个列表并返回是否相同。我怎样才能做到这一点?

我尝试使用 List1.Except(List2) 但它无法比较。

编辑

我创建了自定义 IEqualityComparer:

public class Compare : IEqualityComparer<test>
{
    public bool Equals(test x, test y)
    {
        if (x == null || y == null) return false;

        bool equals = x.ID == y.ID && x.Name == y.Name && x.Remark == y.Remark
            && x.Details == y.Details;
        return equals;
    }
    public int GetHashCode(test codeh)
    {
        return (codeh.ID + codeh.Name + codeh.Remark + codeh.Details).GetHashCode();
    }
}

var 比较器 = new Compare(); List1.Except(List2, Comparer) 这应该有效吗?

编辑

[XmlRoot(ElementName = "Details")]
public class Details
{
    [XmlElement(ElementName = "starttime")]
    public string starttime { get; set; }
    [XmlElement(ElementName = "endtime")]
    public string endtime { get; set; }
    [XmlElement(ElementName = "duration")]
    public string duration { get; set; }
}

[XmlRoot(ElementName = "Remark")]
public class Remark
{
    [XmlElement(ElementName = "RemarkText")]
    public string RemarkText { get; set; }
    [XmlElement(ElementName = "isRemarkVisible")]
    public Boolean IsRemarkVisible { get; set; }
}

[XmlRoot(ElementName = "test")]
public class test
{
    [XmlElement(ElementName = "ID")]
    public string ID { get; set; }
    [XmlElement(ElementName = "Name")]
    public string Name { get; set; }
    public Details Details { get; set; }
    [XmlElement(ElementName = "Remark")]
    public Remark Remark { get; set; }
    [XmlElement(ElementName = "Tags")]
    public Tags Tags { get; set; }
}

[XmlRoot(ElementName = "Tags")]
public class Tags
{
    [XmlElement(ElementName = "TagLocation")]
    public TagLocation[] TagLocation { get; set; }
}

[XmlRoot(ElementName = "TagLocation")]
public class TagLocation
{
    [XmlElement(ElementName = "Id")]
    public string Id { get; set; }
    [XmlElement(ElementName = "TagText")]
    public string TagText { get; set; }
}

[XmlRoot(ElementName = "Tests")]
public class Tests
{
    [XmlElement(ElementName = "test")]
    public test[] test { get; set; }
}

最佳答案

首先修改您的 test 类并实现(覆盖)Equals 函数。这将使您的类能够将自身与另一个对象进行比较并判断两者是否相同。

理想情况下,每个类都应该有自己的 Equals 实现,并且父类不应该比较子对象的内部。但由于您只需要比较 test 类,因此我们在 test 类本身中实现了所有比较逻辑。

[XmlRoot(ElementName = "test")]
public class test
{
    [XmlElement(ElementName = "ID")]
    public string ID { get; set; }
    [XmlElement(ElementName = "Name")]
    public string Name { get; set; }
    public Details Details { get; set; }
    [XmlElement(ElementName = "Remark")]
    public Remark Remark { get; set; }
    [XmlElement(ElementName = "Tags")]
    public Tags Tags { get; set; }

    // override object.Equals
    public override bool Equals(object obj)
    {
        if (obj == null || GetType() != obj.GetType()) return false;

        // modify the code below to suit your needs...
        test objA = (test)obj;
        if (
                this.ID != objA.ID || this.Name != objA.Name
                || this.Details.duration != objA.Details.duration || this.Details.starttime != objA.Details.starttime || this.Details.endtime != objA.Details.endtime
                || this.Remark.IsRemarkVisible != objA.Remark.IsRemarkVisible || this.Remark.RemarkText != objA.Remark.RemarkText
            ) return false;
        if (this.Tags.TagLocation.Length != objA.Tags.TagLocation.Length) return false;
        for (int i = 0; i < this.Tags.TagLocation.Length; i++)
        {
            if (this.Tags.TagLocation[i].Id != objA.Tags.TagLocation[i].Id || this.Tags.TagLocation[i].TagText != objA.Tags.TagLocation[i].TagText) return false;
        }
        return true;    // if everything matched we infer that the objects are equal.
    }

    // override object.GetHashCode
    public override int GetHashCode()
    {
        // modify the code below to generate a unique hash code for your object.
        return base.GetHashCode();
    }
}

然后您可以轻松比较测试类的两个对象。

例如

private void button1_Click(object sender, EventArgs e)
{

    test test1, test2, test3;

    test1 = new test { ID="1", Name ="abc"};
    test1.Details = new Details { duration = "1", starttime = "9.00", endtime = "12.00" };
    test1.Remark = new Remark { IsRemarkVisible = true, RemarkText = "remark1" };
    test1.Tags = new Tags();
    test1.Tags.TagLocation = new TagLocation[] 
    { 
         new TagLocation{ Id = "1", TagText = "tag1" },
         new TagLocation{ Id = "2", TagText = "tag2" } 
    }; 

    test2 = new test { ID = "1", Name = "abc" };
    test2.Details = new Details { duration = "1", starttime = "9.00", endtime = "12.00" };
    test2.Remark = new Remark { IsRemarkVisible = true, RemarkText = "remark2" };
    test2.Tags = new Tags();
    test2.Tags.TagLocation = new TagLocation[] 
    { 
         new TagLocation{ Id = "1", TagText = "tag1" },
         new TagLocation{ Id = "2", TagText = "tag2" } 
    }; 

    test3 = new test { ID = "1", Name = "abc" };
    test3.Details = new Details { duration = "1", starttime = "9.00", endtime = "12.00" };
    test3.Remark = new Remark { IsRemarkVisible = true, RemarkText = "remark2" };
    test3.Tags = new Tags();
    test3.Tags.TagLocation = new TagLocation[] 
    { 
         new TagLocation{ Id = "1", TagText = "tag1" },
         new TagLocation{ Id = "2", TagText = "tag2" } 
    }; 

    MessageBox.Show("test1.Equals(test2) ... " + test1.Equals(test2).ToString());   // shows false
    MessageBox.Show("test2.Equals(test3) ... " + test2.Equals(test3).ToString());   // shows true
}

关于c# - 比较两个复杂的列表对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37021450/

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