c# - 将指数数转换为整数

Question

将“2.3456754342345466E+36”转换为完整号码:

var sm = Convert.ToDouble(splitted[0]) + Convert.ToDouble(splitted[1]);  

**//sm value is === "2.3456754342345466E+36"**

var d = Decimal.Parse(sm.ToString(), 
System.Globalization.NumberStyles.Float);
if (splitted[0].Length ==Convert.ToString(d).Length)
 {
 sum.Add(""+sm);
 }
else
{
 sum.Add(""+splitted[0]);
}

Decimal.Parse(sm.ToString() 抛出:

Value was either too large or too small for a Decimal.

谁能帮忙。

Answer 1

这是因为十进制最大值约为7.9e+28，因此它不适合您的数字。您需要将其存储在double中。当您想要打印数字时，您可以使用带有格式说明符的 ToString() 方法以任何您想要的方式格式化它。例如，F0 将给出不带小数的正数:

var sm = "2.3456754342345466E+36";
var d = double.Parse(sm, System.Globalization.NumberStyles.Float);
Console.WriteLine(d.ToString("F0")); //Prints 2345675434234550000000000000000000000