我有以下扩展方法来序列化我的类....
public static string SerializeToXml<T>(this object obj)
{
XDocument doc = new XDocument();
XmlSerializer ser = new XmlSerializer(typeof(T));
using (var writer = doc.CreateWriter())
{
ser.Serialize(writer, obj);
}
return doc.ToString();
}
这似乎工作正常,并为我的序列化对象返回以下字符串:
<AuthenticatedUser xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Username>mark</Username>
<UserID>4</UserID>
<Roles>
<string>AuthenticatedUsers</string>
</Roles>
<IsValid>false</IsValid>
</AuthenticatedUser>
但是,当我尝试使用下面的方法反序列化该字符串时,出现此错误:
{"The encoding style '<AuthenticatedUser xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\">\r\n <Username>mark</Username>\r\n <UserID>4</UserID>\r\n <Roles>\r\n <string>AuthenticatedUsers</string>\r\n </Roles>\r\n <IsMale>false</IsMale>\r\n</AuthenticatedUser>' is not valid for this call because this XmlSerializer instance does not support encoding. Use the SoapReflectionImporter to initialize an XmlSerializer that supports encoding."}
方法....
public static T DeserializeFromXml<T>(this string xml)
{
var element = XElement.Parse(xml);
XmlSerializer ser = new XmlSerializer(typeof(T));
using (var reader = element.CreateReader())
{
return (T)ser.Deserialize(reader, xml);
}
}
因此,在阅读错误消息后,我更改了反序列化方法以使用 SoadReflectionImporter....
public static T DeserializeFromXml<T>(this string xml)
{
var element = XElement.Parse(xml);
SoapReflectionImporter soap = new SoapReflectionImporter();
var mapping = soap.ImportTypeMapping(typeof(T));
XmlSerializer ser = new XmlSerializer(mapping);
using (var reader = element.CreateReader())
{
return (T)ser.Deserialize(reader, xml);
}
}
但是我现在收到此错误...
{"The encoding style '<AuthenticatedUser xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\">\r\n <Username>mark</Username>\r\n <UserID>4</UserID>\r\n <Roles>\r\n <string>AuthenticatedUsers</string>\r\n </Roles>\r\n <IsValid>false</IsValid>\r\n</AuthenticatedUser>' is not valid for this call. Valid values are 'http://schemas.xmlsoap.org/soap/encoding/' for SOAP 1.1 encoding or 'http://www.w3.org/2003/05/soap-encoding' for SOAP 1.2 encoding."}
有谁知道我哪里出了问题以及如何成功反序列化该字符串?
最佳答案
问题是您正在调用的 Deserialize 方法的重载:
return (T)ser.Deserialize(reader, xml);
调用中的 xml 参数指定编码样式,但在本例中,您传递的是序列化中的 xml。只需删除第二个参数并使用阅读器调用 Deserialize 即可正常工作:
return (T)ser.Deserialize(reader);
关于c# - XmlSerializer - 不支持编码,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3953175/