C# 缩短重复代码的更好方法

Question

以下代码允许我将鼠标悬停在按钮上的图像上，但需要加载大量重复代码。我想知道是否有一种方法可以缩短并允许使用同一段代码但使用不同的按钮名称。

我知道 private void *NAME* 可以是相同的，由不同的按钮使用，并允许我缩短以下内容，但随后让我将鼠标悬停在所有按钮上而不是一次比单独的。

private void button1_Leave(object sender, EventArgs e)
    {
        this.button1.BackgroundImage = ((Image)(Properties.Resources.leave_img));
    }

    private void btnfb_Leave(object sender, EventArgs e)
    {
        this.btnfb.BackgroundImage = ((Image)(Properties.Resources.leave_img));
    }

    void btnfb_MouseMove(object sender, MouseEventArgs e)
    {
        this.btnfb.BackgroundImage = ((Image)(Properties.Resources.hover_img));
    }

    private void btndiscord_Leave(object sender, EventArgs e)
    {
        this.btndiscord.BackgroundImage = ((Image)(Properties.Resources.leave_img));
    }

    void btndiscord_MouseMove(object sender, MouseEventArgs e)
    {
        this.btndiscord.BackgroundImage = ((Image)(Properties.Resources.hover_img));
    }

    private void btn_pp_Leave(object sender, EventArgs e)
    {
        this.btn_pp.BackgroundImage = ((Image)(Properties.Resources.leave_img));
    }

    void btn_pp_MouseMove(object sender, MouseEventArgs e)
    {
        this.btn_pp.BackgroundImage = ((Image)(Properties.Resources.hover_img));
    }

    private void btnhelp_Leave(object sender, EventArgs e)
    {
        this.btnhelp.BackgroundImage = ((Image)(Properties.Resources.leave_img));
    }

    void btnhelp_MouseMove(object sender, MouseEventArgs e)
    {
        this.btnhelp.BackgroundImage = ((Image)(Properties.Resources.hover_img));
    }

    private void btnsave_Leave(object sender, EventArgs e)
    {
        this.btnsave.BackgroundImage = ((Image)(Properties.Resources.leave_img));
    }

    void btnsave_MouseMove(object sender, MouseEventArgs e)
    {
        this.btnsave.BackgroundImage = ((Image)(Properties.Resources.hover_img));
    }

    private void btnmini_Leave(object sender, EventArgs e)
    {
        this.btnmini.BackgroundImage = ((Image)(Properties.Resources.leave_img));
    }

Answer 1

您可以将所有事件连接到同一个处理程序...

private void MyButtonLeaveHandler(object sender, EventArgs e)
{
 Button button = sender as Button;
 if (button != null)
 { 
     button.BackgroundImage = ((Image)(Properties.Resources.leave_img));
 }
}

说

this.button1.Leave += MyButtonLeaveHandler;
this.btnfb.Leave += MyButtonLeaveHandler;

同样，您可以为 MouseLeave 事件创建另一个通用处理程序