我有一个列表,我的目标是确定该列表中的值超过特定值的次数。
例如,如果我的列表是: 列表 = {0, 0, 3, 3, 4, 0, 4, 4, 4} 我想知道有两个实例,我的值在列表中大于 2 并保持在 2 以上。所以在这种情况下有 2 个实例,因为它一度低于 2 并再次高于它。
private void Report_GeneratorButton_Click(object sender, EventArgs e)
{
//Lists
var current = _CanDataGraph._DataPoints[CanDataGraph.CurveTag.Current].ToList();
var SOC = _CanDataGraph._DataPoints[CanDataGraph.CurveTag.Soc].ToList();
var highcell = _CanDataGraph._DataPoints[CanDataGraph.CurveTag.HighestCell].ToList();
var lowcell = _CanDataGraph._DataPoints[CanDataGraph.CurveTag.LowestCell].ToList();
//Seperates current list into charging, discharging, and idle
List<double> charging = current.FindAll(i => i > 2);
List<double> discharging = current.FindAll(i => i < -2);
List<double> idle = current.FindAll(i => i < 2 && i > -2);
//High cell
List<double> overcharged = highcell.FindAll(i => i > 3.65);
int ov = overcharged.Count;
if (ov > 1)
{
Console.WriteLine("This Battery has gone over Voltage!");
}
else
{
Console.WriteLine("This battery has never been over Voltage.");
}
//Low cell
List<double> overdischarged = lowcell.FindAll(i => i > 3.65);
int lv = overdischarged.Count;
if (lv > 1)
{
Console.WriteLine("This Battery has been overdischarged!");
}
else
{
Console.WriteLine("This battery has never been overdischarged.");
}
//Each value is 1 second
int chargetime = charging.Count;
int dischargetime = discharging.Count;
int idletime = idle.Count;
Console.WriteLine("Charge time: " + chargetime + "s" + "\n" + "Discharge time: " + dischargetime + "s" + "\n" + "Idle time: " + idletime);
}
我当前的代码是这样并输出:
This battery has never been over Voltage.
This battery has never been overdischarged.
Charge time: 271s
Discharge time: 0s
Idle time: 68
最佳答案
有很多方法可以解决这个问题;我的建议是将它分解成许多较小的问题,然后编写一个简单的方法来解决每个问题。
这是一个更简单的问题:给定一个 T
序列,返回一个删除了“双倍”项目的 T
序列:
public static IEnumerable<T> RemoveDoubles<T>(
this IEnumerable<T> items)
{
T previous = default(T);
bool first = true;
foreach(T item in items)
{
if (first || !item.Equals(previous)) yield return item;
previous = item;
first = false;
}
}
太棒了。这有什么帮助?因为现在您的问题的解决方案是:
int count = myList.Select(x => x > 2).RemoveDoubles().Count(x => x);
跟随。
如果您将 myList
作为 {0, 0, 3, 3, 4, 0, 4, 4, 4}
那么 Select 的结果
是 {false, false, true, true, true, false, true, true, true}
。
RemoveDoubles
的结果是 {false, true, false, true}
。
Count
的结果是 2,这是想要的结果。
尽可能使用现成的部件。如果做不到,请尝试解决一个简单、一般的问题,从而满足您的需求;现在您有了一个工具,可用于需要您删除序列中重复项的其他任务。
关于c# - 查找实例在列表中出现的次数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56796892/