c# - 在 C# 中从 List<string> 构建字符串

Question

List<string>有 ("ABC","","DEF","","XYZ")，如何从 C# 中的列表中获取字符串“ABC::DEF::XYZ”？

已添加

List<string> strings = new List<string> {"ABC","","DEF","","XYZ"};
string joined = string.Join("::", strings.ToArray());
Console.WriteLine(joined);

给出 ABC::::DEF::::XYZ , 不是 ABC::DEF::XYZ , 如何跳过列表中的空字符串 ("")？

Answer 1

你可以这样做:

List<string> strings = ...
string joined = string.Join(":", strings.ToArray());

在 .NET 4.0 中，您可以省略 ToArray() 调用。

编辑:根据您的更新表明您想要跳过空字符串并使用两个冒号作为分隔符，您可以:

// Use !string.IsNullOrEmpty or !string.IsNullOrWhiteSpace if more appropriate.   
string[] filtered = list.Where(s => s != string.Empty) 
                        .ToArray();

string joined = string.Join("::", filtered);