在链接上,我向您展示了我程序中的所有类(class)
我的 customerframe
类中有这样的属性:
public string firstName { get; set; }
public string lastName { get; set; }
public CustomerFiles.Phone phone { get; set; }
public CustomerFiles.Email email { get; set; }
public CustomerFiles.Address addressinfo { get; set; }
public string city { get; set; }
public CustomerFiles.Countries countryinfo { get; set; }
public string street { get; set; }
public string zipcode { get; set; }
但我的问题是,在执行此操作时,我得到指向这 4 个属性的错误
public CustomerFiles.Phone phone { get; set; }
public CustomerFiles.Email email { get; set; }
public CustomerFiles.Address addressinfo { get; set; }
public CustomerFiles.Countries countryinfo { get; set; }
错误是这样的
inconsistent accessibility property type is less accessible than property
在类里面,我将执行以下操作:
contact.FirstName = tbFirstName.Text;
firstName = contact.FirstName;
contact.LastName = tbLastName.Text;
lastName = contact.LastName;
contact.PhoneData = tbCellPhone.Text;
phone = contact.PhoneData;
contact.EmailData = tbHomePhone.Text;
email = contact.EmailData;
//inside address class
address.City = tbCity.Text;
city = address.City;
address.Country = cbCountry.Text;
countryinfo = address.Country;
address.Street = tbStreet.Text;
street = address.Street;
address.ZipCode = tbZipCode.Text;
zipcode = address.ZipCode;
但为什么我的属性会出现问题?我该如何解决这个问题才能让它发挥作用?提前致谢
最佳答案
显然,CustomerFiles.Phone
类型(或者它的包含类型 CustomerFiles
,如果它是类型而不是命名空间)没有 public 的可见性
。由于您创建的返回类型的属性是公共(public)的,因此类型本身也需要是 public
。
关于c# - 无法声明具有不同属性类型的属性,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8490467/