我浏览了该站点上的问题,但没有找到与我的特定问题相匹配的问题。
假设我有以下内容:
Product[] store1 = { new Product { Name = "apple", Code = 9, Code1="1" },
new Product { Name = "orange", Code = 4 } };
Product[] store2 = { new Product { Name = "apple", Code = 9, Code2="2" },
new Product { Name = "lemon", Code = 12 } };
与:
public class Product : IEquatable<Product>
{
public string Name { get; set; }
public int Code { get; set; }
public string Code1 { get; set; }
public string Code2 { get; set; }
public bool Equals(Product other)
{
//Check whether the compared object is null.
if (Object.ReferenceEquals(other, null)) return false;
//Check whether the compared object references the same data.
if (Object.ReferenceEquals(this, other)) return true;
//Check whether the products' properties are equal.
return Code.Equals(other.Code) && Name.Equals(other.Name);
}
// If Equals() returns true for a pair of objects
// then GetHashCode() must return the same value for these objects.
public override int GetHashCode()
{
//Get hash code for the Name field if it is not null.
int hashProductName = Name == null ? 0 : Name.GetHashCode();
//Get hash code for the Code field.
int hashProductCode = Code.GetHashCode();
//Calculate the hash code for the product.
return hashProductName ^ hashProductCode;
}
}
如何返回一个单一的 Enumerable,其中 store1 的数据在匹配时被 store2 的数据覆盖,并且在非匹配时刚从 store2 插入到 store1 中。基本上,我正在寻找与 TSQL Merge 语句等效的 C#。
在一天结束时运行这个:
foreach (var product in union)
Console.WriteLine(product.Name + " " + product.Code + " " + product.Code1 + " " + product.Code2);
我想回去:
苹果 9 1 2
橙色 4
柠檬 12
但是当我运行这个时:
IEnumerable<Product> union = store1.Union(store2);
我得到:
苹果 9 1
橙色 4
柠檬 12
当我运行这个时:
IEnumerable<Product> union = store1.Concat(store2);
我得到:
苹果 9 1
橙色 4
苹果 9 2
柠檬 12
在此先感谢您的帮助。
最佳答案
//
// Summary:
// Produces the set union of two sequences by using the default equality comparer.
//
// Parameters:
// first:
// An System.Collections.Generic.IEnumerable<T> whose distinct elements form
// the first set for the union.
//
// second:
// An System.Collections.Generic.IEnumerable<T> whose distinct elements form
// the second set for the union.
//
// Type parameters:
// TSource:
// The type of the elements of the input sequences.
//
// Returns:
// An System.Collections.Generic.IEnumerable<T> that contains the elements from
// both input sequences, excluding duplicates.
//
// Exceptions:
// System.ArgumentNullException:
// first or second is null.
public static IEnumerable<TSource> Union<TSource>(this IEnumerable<TSource> first, IEnumerable<TSource> second);
因为函数的原因
excluding duplicates.
所以你必须为 Product[] 编写联合函数
public static class ProductExtension
{
public static IEnumerable<T> Union<T>(this IEnumerable<T> store1, IEnumerable<T> store2)
{
List<T> List = new List<T>();
foreach (var item in store2)
{
if (store1.Any(n=>n.Equals(item)))
{
var obj = store1.First(n => n.Equals(item));
foreach (System.Reflection.PropertyInfo pi in obj.GetType().GetProperties())
{
object v1 = pi.GetValue(obj, null);
object v2 = pi.GetValue(item, null);
var value = v1;
if (v2 != null && (v1 == null || v1.ToString() == string.Empty) && v1 != v2)
{
value = v2;
}
pi.SetValue(obj, value, null);
}
List.Add(obj);
}
else {
List.Add(item);
}
}
foreach (var item in store1) {
if(!store2.Any(n=>n.Equals(item))){
List.Add(item);
}
}
return List.AsEnumerable();
}
}
关于c# - 我如何从另一个可枚举的 c# 中插入一个可枚举的,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16095895/