c# - 在 Controller 体内访问 Web API 反序列化/序列化方法

Question

有没有办法反序列化/序列化 JSON POST 内容/响应在 Web API Controller 的主体中，其方式与 Controller 反序列化/序列化的方式完全相同JSON 内容/响应是参数/显式类型吗？

我的动机是我正在尝试构建一个“神奇”的 API Controller ，如果开发人员没有足够的时间构建强类型操作来访问它们，它可以快速提供对我的服务命令的访问。假设我有以下操作:

public Brownie Brownie(BrownieInputModel inputModel)
{
    ...
    var brownie = brownieService.GetBrownie(inputModel);
    return brownie;
}

public Pizza Pizza(PizzaInputModel inputModel)
{
    ...
    var pizza = pizzaService.GetPizza(inputModel);
    return pizza;
}

是否有可能做这样的事情(在伪代码中):

public object FoodStuff(string methodName)
{
    var inputModel = WebApi.Deserialize(Request.JsonContent); // <-- pseudo
    var serviceMethod = GetServiceMethodFromMethodName(methodName);
    var result = serviceMethod.Execute();
    return WebApi.Serialize(result); // <-- pseudo
}

Answer 1

我认为HttpRequestMessage和 HttpResponseMessage类可以帮你解决这个问题。使用它们，您的代码可以看起来像这样:

public async Task<HttpResponseMessage> Post(
    string methodName, HttpRequestMessage request)
{
    HttpResponseMessage response;
    switch (methodName)
    {
        case "brownie":
            response = await HandleBrownieAsync(request);
            break;
        case "pizza":
            response = await HandlePizzaAsync(request);
            break;
        default:
            throw new NotSupportedException();
    }
    return response;
}

private async Task<HttpResponseMessage> HandleBrownieAsync(HttpRequestMessage request)
{
    var brownie = await GetRequestContentAsync<Brownie>(request);
    return await CreateJsonResponseAsync(brownie);
}

private async Task<HttpResponseMessage> HandlePizzaAsync(HttpRequestMessage request)
{
    var pizza = await GetRequestContentAsync<Pizza>(request);
    return await CreateJsonResponseAsync(pizza);
}

private async Task<T> GetRequestContentAsync<T>(HttpRequestMessage request)
{
    var contentString = await request.Content.ReadAsStringAsync();
    return await JsonConvert.DeserializeObjectAsync<T>(contentString);
}

private async Task<HttpResponseMessage> CreateJsonResponseAsync<T>(T content)
{
    var response = new HttpResponseMessage(HttpStatusCode.OK)
    {
        Content = new StringContent(
            await JsonConvert.SerializeObjectAsync(content),
            Encoding.UTF8,
            "application/json")
    };
    return response;
} 

如果您使用这些简化模型:

public class Brownie
{
    public bool HasNuts { get; set; }
}

public class Pizza
{
    public string CheeseType { get; set; }
}

然后你可以发起POST请求:

URL:http://api.url?methodName=brownie， 正文:{"hasNuts":true}

或

URL:http://api.url?methodName=pizza， 主体:{"cheeseType":"Mozzarella"}