c# - 如何将多个对象发送到 WCF 方法

Question

我有一个 wcf 服务，我正在按以下方法向其发送一个列表。 但是我想发送两个参数，如下面的方法意味着可以是一个列表或任何与服务层中的实体相同的对象，通过 post 方法。 这可能吗？

下面是我将对象数组发送到服务的过程。它运行良好。

jquery 代码:

      var listOfObjects=new Array();

      //creating list of objects
      for(var i=0;i<5;i++)
       {   var MyEntity=new Object();
           MyEntity.TestId =i;
           MyEntity.TestId =i+"testName";
           listOfObjects.push(MyEntity);
       }

       var jsonList=JSON.stringify(listOfObjects);
       var dataToSend = '{"myEntity":'+jsonData+'';

        //Saving info
        $.ajax({
            type: "POST",
            async: false,
            data: dataToSend,
            url: "../ServiceLayer/myService.svc/SaveResults",
            contentType: "application/json; charset=utf-8",
            dataType: "json",          
            success: function () {
                alert("success");
            },
            error: function () {
                alert("Error");
            }
        });

WCF:

    [WebInvoke(Method = "POST", RequestFormat = WebMessageFormat.Json,
     ResponseFormat = WebMessageFormat.Json, BodyStyle = WebMessageBodyStyle.WrappedRequest)]
    public void SaveLabResults(List<MyEntity> myEntity)
    {
          var lstEntities=myEntity;
    }

实体:

[DataContract]
public class MyEntity
{
    [DataMember]
    public string TestId { get; set; }
    [DataMember]
    public string TestName { get; set; }
}

谢谢

Answer 1

当然可以，只需添加另一个参数即可。

   [WebInvoke(Method = "POST", RequestFormat = WebMessageFormat.Json,
     ResponseFormat = WebMessageFormat.Json, BodyStyle = WebMessageBodyStyle.WrappedRequest)]
    public void SaveLabResults(List<MyEntity> myEntity,List<MyEntity> myEntity2)
    {
          var lstEntities=myEntity;
          var lstEntities2=myEntity2;
    }

和:

var dataToSend = '{"myEntity":'+jsonData+', "myEntity2":'+jsonData2+' }';
//Saving info
$.ajax({
    type: "POST",
    async: false,
    data: dataToSend,
    url: "../ServiceLayer/myService.svc/SaveResults",
    contentType: "application/json; charset=utf-8",
    dataType: "json",          
    success: function () {
        alert("success");
    },
    error: function () {
        alert("Error");
    }
});