应用程序的一些背景。这是我拥有的 WASP 和 SMPP 发送器帐户。
我有一个列表<>,其中包含一个对象,该对象具有 SMPP PDU 和发送消息所需的所有对象。 此列表包含一个称为“路由标签”的属性,路由标签将指示将 PDU 提交给哪个服务提供商(Vodacom、MTN、Cell C)。
我有另一个帐户列表,我可以在其中绑定(bind)到 SMPP 服务器并通过它发送消息。该列表还包含路由标签,并具有发送者帐户的名称。例如,Vodacom 的路由标签是“D082”,我有两个可以同时绑定(bind)的帐户。
我现在需要获取第一个 List<> 并更新字段。假设第一个 List<> 有 1000 个项目。我需要将这些(或多或少均匀地)分配到我所拥有的所有帐户中,用于出现在第二个列表 <> 中的每个“路由标签”。
我更愿意使用 linq 或 lambda 实现所需的功能。
已编辑:添加了代码示例,以便您好心的人可以帮助我 :-) 很抱歉标准不佳,但我很快为你们删除了一些代码。我希望这有助于解决我的问题。
static void Main(string[] args)
{
List<MobileAccounts> TransmitterAccounts = new List<MobileAccounts>();//This list contains my transmitter accounts
MobileAccounts item = new MobileAccounts();
item.FriendlyName = "Vodacom 1";
item.RoutingLabel = "D082";
TransmitterAccounts.Add(item);
MobileAccounts item1 = new MobileAccounts();
item1.FriendlyName = "Vodacom 2";
item1.RoutingLabel = "D082";
TransmitterAccounts.Add(item1);
MobileAccounts item2 = new MobileAccounts();
item2.FriendlyName = "MTN 1";
item2.RoutingLabel = "D083";
TransmitterAccounts.Add(item2);
MobileAccounts item3 = new MobileAccounts();
item3.FriendlyName = "MTN 2";
item3.RoutingLabel = "D083";
TransmitterAccounts.Add(item3);
MobileAccounts item4 = new MobileAccounts();
item4.FriendlyName = "MTN 3";
item4.RoutingLabel = "D083";
TransmitterAccounts.Add(item4);
MobileAccounts item5 = new MobileAccounts();
item5.FriendlyName = "CellC 1";
item5.RoutingLabel = "D084";
TransmitterAccounts.Add(item5);
MobileAccounts item6 = new MobileAccounts();
item6.FriendlyName = "CellC 2";
item6.RoutingLabel = "D084";
TransmitterAccounts.Add(item6);
List<SubmitSm> col = new List<SubmitSm>();//this list contains messages in a queue ready for sending
SubmitSm sitem = new SubmitSm();
sitem.DestAddr = "0722222222";//Vodacom number
sitem.RoutingLabel = "D082";
col.Add(sitem);
SubmitSm sitem1 = new SubmitSm();
sitem1.DestAddr = "0722222220";//Vodacom number
sitem1.RoutingLabel = "D082";
col.Add(sitem1);
SubmitSm sitem2 = new SubmitSm();
sitem2.DestAddr = "0722221212";//Vodacom number
sitem2.RoutingLabel = "D082";
col.Add(sitem2);
SubmitSm sitem3 = new SubmitSm();
sitem3.DestAddr = "0830000000";//MTN number
sitem3.RoutingLabel = "D083";
col.Add(sitem3);
SubmitSm sitem4 = new SubmitSm();
sitem4.DestAddr = "0833746005";//MTN number
sitem4.RoutingLabel = "D083";
col.Add(sitem4);
SubmitSm sitem5 = new SubmitSm();
sitem5.DestAddr = "0749999998";//CellC number
sitem5.RoutingLabel = "D084";
col.Add(sitem5);
/*
* Now this is where I will need
* to split all the messages in "col"
* amongst all the transmitter accounts
* I have.
*/
}
public class MobileAccounts
{
/*Please note not all items
are in this class. I have
* removed some as they are not
* neccessary for this demo code.
*/
//[DataMember]
public string FriendlyName;
//[DataMember]
public string BindName;
//[DataMember]
public string BindPassword;
//[DataMember]
public string BindHost;
//[DataMember]
public string BindPort;
//[DataMember]
public string BindType;
//[DataMember]
public string ProviderCode;
//[DataMember]
public string RoutingLabel;
}
public class SubmitSm
{
/*Please note not all items
are in this class. I have
* removed some as they are not
* neccessary for this demo code.
*/
public byte DefaultMessageId { get; set; }
public string DestAddr { get; set; }
public byte DestAddrNpi { get; set; }
public byte DestAddrTon { get; set; }
public string MessageText { get; set; }
public byte PriorityFlag { get; set; }
public byte ProtocolId { get; set; }
public byte RegisteredDelivery { get; set; }
public string ScheduleDeliveryTime { get; set; }
public string ServiceType { get; set; }
public string SourceAddr { get; set; }
public byte SourceAddrNpi { get; set; }
public byte SourceAddrTon { get; set; }
public string ValidityPeriod { get; set; }
public string RoutingLabel { get; set; }
}
感谢所有做出贡献的人。 @NinjaNye 您的解决方案很接近但不完全符合我的要求。不过,我非常感谢您的努力。
我认为我快到了,但我还在挣扎。谁能帮我找出下面显示的子选择:
List<IGrouping<string, MobileAccounts>> sad1 = TransmitterAccounts.GroupBy(y => y.RoutingLabel).ToList();
col = (List<SubmitSm>)col.Select
(x =>
{
x.ServiceType = sad1.Where
(z =>
z.Key== x.ServiceType
)
.Select
(y =>
new
{
//this should return the Transmitter account that has the lowest count
TransmitterAccount = y.OrderBy(ui => x.ServiceType.Count()).Select(ui => ui.FriendlyName).First()
}
).First().TransmitterAccount;
return x;
}
).ToList();
最佳答案
我在这里看到的 Linq 的唯一用途是使用 .Skip()
和 .Take()
但是我创建了一个扩展方法来整理东西向上一点。这意味着您可以简单地编写以下代码来拆分任何 IEnumerable
。
// In your example above you need to replace `items` with your `col` variable
var result = items.Split(transmitter.Count());
扩展方法
http://www.ninjanye.co.uk/2013/07/splitting-distributing-list-objects.html
public static class EnumerableExtensions
{
public static IEnumerable<IEnumerable<T>> Split<T>(this IEnumerable<T> source, int groups)
{
var listedSource = source.ToList();
int extra;
int groupSize = Math.DivRem(listedSource.Count(), groups, out extra);
while (listedSource.Any())
{
int newSize = groupSize;
if (extra > 0)
{
newSize++;
extra--;
}
yield return listedSource.Take(newSize);
listedSource = listedSource.Skip(newSize).ToList();
}
}
}
结果
我把它设置成一个快速命令程序来测试
以下是一些结果,您可以看到项目是如何拆分的:
初始帖子(现已重构)
像这样应该可以做到...但是我已经简化了示例
// This is your transmitter count
int groups = 4;
// These are your SMS's
List<int> values = new List<int>(){1,2,3,4,5,6,7,8,9};
//Calculate group size
int extra;
int groupSize = Math.DivRem(values.Count, groups, out extra);
var result = new List<IEnumerable<int>>();
while (values.Any())
{
int newSize = groupSize;
if (extra > 0)
{
// Account for extras
newSize++;
extra--;
}
result.Add(values.Take(newSize));
values = values.Skip(newSize).ToList();
}
return result;
关于c# - LINQ/Lambda 通过将列表项分成偶数组来更新列表项,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17616173/